Pattern: Use of $ on iterator name in for loop
Issue: -
The variable is named var, and can be expanded to its value with $var.
The for loop expects the variable's name, not its value (and the name can not be specified indirectly).
Example of incorrect code:
for $var in *
do
echo "$var"
doneExample of correct code:
for var in *
do
echo "$var"
done