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chore: change log object #553

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chore: change log object #553

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SunsetWolf
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@SunsetWolf SunsetWolf commented Feb 5, 2025 •
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Description

Motivation and Context

How Has This Been Tested?

  • If you are adding a new feature, test on your own test scripts.

Screenshots of Test Results (if appropriate):

  1. Your own tests:

Types of changes

  • Fix bugs
  • Add new feature
  • Update documentation

📚 Documentation preview 📚: https://RDAgent--553.org.readthedocs.build/en/553/

@SunsetWolf SunsetWolf changed the title chore: Change log object chore: change log object Feb 5, 2025
you-n-g
you-n-g reviewed Feb 6, 2025
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rdagent/log/logger.py Outdated
@@ -110,6 +121,169 @@ def file_format(self, record: "Record", raw: bool = False) -> str:
return "{message}"
return "{time:YYYY-MM-DD HH:mm:ss.SSS} | {level: <8} | {name}:{function}:{line} - {message}\n"

def format_pkl(self, base_path: str | Path):
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move them to UI

github-advanced-security[bot]
github-advanced-security bot found potential problems Feb 19, 2025
View reviewed changes
github-advanced-security[bot]
github-advanced-security bot found potential problems Feb 24, 2025
View reviewed changes
rdagent/log/server/app.py
for file in files:
if file:
p = Path(f'./uploads/{scenario}')
if not p.exists():

Check failure

Code scanning / CodeQL

Uncontrolled data used in path expression High

This path depends on a
user-provided value
Loading
.

Copilot Autofix AI 7 days ago

To fix the problem, we need to validate and sanitize the scenario input before using it to construct file paths. The best way to do this is to ensure that the scenario input does not contain any special characters or sequences that could lead to path traversal. We can use the werkzeug.utils.secure_filename function to sanitize the scenario input.

  • Import the secure_filename function from werkzeug.utils.
  • Use secure_filename to sanitize the scenario input before using it in the file path.
Suggested changeset 1
rdagent/log/server/app.py

Autofix patch

Autofix patch
Run the following command in your local git repository to apply this patch
cat << 'EOF' | git apply
diff --git a/rdagent/log/server/app.py b/rdagent/log/server/app.py
--- a/rdagent/log/server/app.py
+++ b/rdagent/log/server/app.py
@@ -6,2 +6,3 @@
 from flask_cors import CORS
+from werkzeug.utils import secure_filename
 
@@ -227,3 +228,3 @@
     # 获取请求体中的字段
-    scenario = request.form.get('scenario')
+    scenario = secure_filename(request.form.get('scenario'))
     files = request.files.getlist('files')
EOF
@@ -6,2 +6,3 @@
from flask_cors import CORS
from werkzeug.utils import secure_filename

@@ -227,3 +228,3 @@
# 获取请求体中的字段
scenario = request.form.get('scenario')
scenario = secure_filename(request.form.get('scenario'))
files = request.files.getlist('files')
Copilot is powered by AI and may make mistakes. Always verify output.
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Please select one or more of the options
rdagent/log/server/app.py
if file:
p = Path(f'./uploads/{scenario}')
if not p.exists():
p.mkdir(parents=True, exist_ok=True)

Check failure

Code scanning / CodeQL

Uncontrolled data used in path expression High

This path depends on a
user-provided value
Loading
.

Copilot Autofix AI 7 days ago

To fix the problem, we need to validate and sanitize the scenario variable before using it to construct file paths. The best way to do this is to ensure that the scenario variable does not contain any special characters or sequences that could lead to path traversal. We can use the werkzeug.utils.secure_filename function to sanitize the scenario variable.

  1. Import the secure_filename function from werkzeug.utils.
  2. Use secure_filename to sanitize the scenario variable before using it in the file path.
Suggested changeset 1
rdagent/log/server/app.py

Autofix patch

Autofix patch
Run the following command in your local git repository to apply this patch
cat << 'EOF' | git apply
diff --git a/rdagent/log/server/app.py b/rdagent/log/server/app.py
--- a/rdagent/log/server/app.py
+++ b/rdagent/log/server/app.py
@@ -6,2 +6,3 @@
 from flask_cors import CORS
+from werkzeug.utils import secure_filename
 
@@ -227,3 +228,3 @@
     # 获取请求体中的字段
-    scenario = request.form.get('scenario')
+    scenario = secure_filename(request.form.get('scenario'))
     files = request.files.getlist('files')
EOF
@@ -6,2 +6,3 @@
from flask_cors import CORS
from werkzeug.utils import secure_filename

@@ -227,3 +228,3 @@
# 获取请求体中的字段
scenario = request.form.get('scenario')
scenario = secure_filename(request.form.get('scenario'))
files = request.files.getlist('files')
Copilot is powered by AI and may make mistakes. Always verify output.
Positive Feedback
Negative Feedback

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Please help us improve GitHub Copilot by sharing more details about this comment.

Please select one or more of the options
rdagent/log/server/app.py
if not data:
return jsonify({"error": "No JSON data received"}), 400
except Exception as e:
return jsonify({"error": str(e)}), 500

Check warning

Code scanning / CodeQL

Information exposure through an exception Medium

Stack trace information
Loading
flows to this location and may be exposed to an external user.

Copilot Autofix AI 7 days ago

To fix the problem, we need to modify the exception handling in the /receive route to log the detailed error message on the server and return a generic error message to the user. This involves:

  1. Importing the traceback module to capture the stack trace.
  2. Logging the stack trace on the server.
  3. Returning a generic error message to the user.
Suggested changeset 1
rdagent/log/server/app.py

Autofix patch

Autofix patch
Run the following command in your local git repository to apply this patch
cat << 'EOF' | git apply
diff --git a/rdagent/log/server/app.py b/rdagent/log/server/app.py
--- a/rdagent/log/server/app.py
+++ b/rdagent/log/server/app.py
@@ -259,3 +259,5 @@
     except Exception as e:
-        return jsonify({"error": str(e)}), 500
+        import traceback
+        traceback.print_exc()  # Log the stack trace on the server
+        return jsonify({"error": "An internal error has occurred!"}), 500
 
EOF
@@ -259,3 +259,5 @@
except Exception as e:
return jsonify({"error": str(e)}), 500
import traceback
traceback.print_exc() # Log the stack trace on the server
return jsonify({"error": "An internal error has occurred!"}), 500

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rdagent/log/server/app.py
return send_from_directory(app.static_folder, fn)

if __name__ == '__main__':
app.run(debug=True, host='0.0.0.0', port=19899)

Check failure

Code scanning / CodeQL

Flask app is run in debug mode High

A Flask app appears to be run in debug mode. This may allow an attacker to run arbitrary code through the debugger.

Copilot Autofix AI 7 days ago

To fix the problem, we need to ensure that the Flask application does not run in debug mode in a production environment. The best way to achieve this is to use an environment variable to control the debug mode. This way, we can set the environment variable to enable debug mode during development and disable it in production.

  1. Import the os module to access environment variables.
  2. Modify the app.run call to set the debug parameter based on the value of an environment variable (e.g., FLASK_DEBUG).
Suggested changeset 1
rdagent/log/server/app.py

Autofix patch

Autofix patch
Run the following command in your local git repository to apply this patch
cat << 'EOF' | git apply
diff --git a/rdagent/log/server/app.py b/rdagent/log/server/app.py
--- a/rdagent/log/server/app.py
+++ b/rdagent/log/server/app.py
@@ -276,2 +276,4 @@
 if __name__ == '__main__':
-    app.run(debug=True, host='0.0.0.0', port=19899)
+    import os
+    debug_mode = os.getenv('FLASK_DEBUG', 'False').lower() in ['true', '1', 't']
+    app.run(debug=debug_mode, host='0.0.0.0', port=19899)
EOF
@@ -276,2 +276,4 @@
if __name__ == '__main__':
app.run(debug=True, host='0.0.0.0', port=19899)
import os
debug_mode = os.getenv('FLASK_DEBUG', 'False').lower() in ['true', '1', 't']
app.run(debug=debug_mode, host='0.0.0.0', port=19899)
Copilot is powered by AI and may make mistakes. Always verify output.
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@SunsetWolf @you-n-g