How to concatenate multiple yaml files into an array

[chevdor]

a.yaml:

n: 1

b.yaml:

n: 2

I would need the output ot be as shown below and the solution to work with *.yaml as input:

[
   { n: 1 },
   { n: 2 }
]

or the yaml equivalent.

[chevdor]

This option only works for 2 files. I should have mentioned that I need to process *.yaml based on the example above.
Edit: Question fixed.

[joao-paulo-parity]

For 2 files:

jq --arg first "$(yq -o=json eval a.yml)" --arg second "$(yq -o=json eval b.yml)" -n '[$first | fromjson] + [$second | fromjson]'

For a variable amount of files:

#!/bin/bash

args=()

expr=""
arg_i=0
for file in "$@"; do
  args+=(--arg "arg${arg_i}" "$(yq -o=json eval "$file")")
  expr+=" [\$arg${arg_i} | fromjson] +"
  arg_i=$(( arg_i + 1 ))
done
expr="${expr:0: $(( ${#expr} - 2 ))}"

jq "${args[@]}" -n "$expr"

[chevdor]

Extra points is tihs is using yq only :)

[mikefarah]

yq ea '[.]' data1.yaml data2.yaml

Explanation:

• use ea to execute against all the yaml content at once (by default, yq runs against one document at a time)
• surround everything by an array

[mikefarah]

Though this doesn't have the format you had, are you trying to get JSON? You can use the -o=j flag to get that layout

[chevdor]

Perfect, this is exaclty what I needed ! Thank you.
To summarize, json was indeed what I was after and it works fine with yq ea -o=j '[.]' *.yaml.