added more problem - Prime numbers related

Author: ProRasel

Check-Prime/Prime-Numbers.md

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+## 7.1 Check Prime: 
+
+### S-1: The problem 
+For a given number, check whether the number is a prime number or not.
+
+### S-2: Hint
+A number is a prime number. If that number is only divisible by 1 and the number itself. 
+
+This means a prime number is not divisible by any numbers between 1 and the number itself. 
+
+So, to check prime, you can start dividing the number from 2. And then increase it by 1. If the number gets divided, then it’s not a prime number. 
+
+### S-3: The solution 
+
+```python
+def is_prime(num):
+   for i in range(2,num):
+       if (num % i) == 0:
+           return False
+   return True
+
+
+num = int(input("Enter a number: "))
+
+check_prime = is_prime(num)
+
+if check_prime:
+   print('Your number is a Prime')
+else:
+   print('Your number is not a Prime')
+```
+
+[try it: button]
+
+### S-4: Explanation
+The core part of the algorithm is the is_prime function. 
+
+There we start a for loop the range(2, num). Because we want to know that the number is not divisible by any number except 1 or the number itself. 
+
+For example, 29. It’s only divisible by 1 or 29. 
+
+So, to test whether the number is divisible by any number greater than 1. We started the for loop from 2. And then going to before the num variable. 
+
+To check the number divisible, we check the remainder to be equal to 0. If the number is gets divided, the remainder will be 0. 
+
+So, if the number gets divided by, it’s not a prime number. That’s why we will return False.
+
+If the number doesn’t get divided by any numbers smaller than the number, it won’t go inside the if block. It will finish all the numbers up to the num. 
+
+Then we will return True. Because it didn’t get divided, by any numbers. Hence, it will be a prime number.
+
+### S-5: Many Solution
+There are other solutions to this problem as well. We encourage you to google, “check prime number python”. In that way, you will learn a lot. 
+
+### S-6: Take Away
+A prime number is only divisible by 1 and the number itself. 
+
+ 
+[![Next Page](assets/next-button.png)](..README.md)
+ 
+
+###### tags: `programmig-hero` `python` `float` `int` `math`

Computations/Calculate-Grades.md

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+## 6.3 Calculate grades
+
+### S-1: The problem
+Calculate grade of five subjects. 
+
+### S-2: Hint
+So, you have to take five inputs. These will be the marks of five subjects. Then, create the average. 
+
+Once you have the average. It just running an if-else. And decide the grade. 
+
+### S-3: The Solution
+```python
+print('Enter your marks:')
+sub1=int(input("First subject: "))
+sub2=int(input("Second subject: "))
+sub3=int(input("Third subject: "))
+sub4=int(input("Fourth subject: "))
+sub5=int(input("Fifth subject: "))
+ 
+avg=(sub1+sub2+sub3+sub4+sub4)/5
+ 
+if avg >= 90:
+   print("Grade: A")
+elif avg >= 80:
+   print("Grade: B")
+elif avg >= 70:
+   print("Grade: C")
+elif avg >=60:
+   print("Grade: D")
+else:
+   print("Grade: F")
+```
+**[Try It:](/https://play.google.com/store/apps/details?id=com.learnprogramming.codecamp)**
+
+### S-4: Explanation
+Calculation of average is easy. Add them all and then divide by the count. As we are taking numbers for 5 subjects we are dividing the total by 5. 
+
+After that, we are running a simple if-else to determine the grade. 
+
+ 
+[![Next Page](assets/next-button.png)](Gravitational-Force.md)
+ 
+
+###### tags: `programmig-hero` `python` `float` `int` `math`

Computations/Complex-Interest.md

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+## 6.2: Compound Interest
+
+### S-1: The Problem
+Take money borrowed, interest and duration as input. Then, compute the compound interest rate.
+
+### S-2: Hint
+Compound interest formula is:
+
+A = P(1+r/100)t
+
+Here, P is the principal amount; it is the amount that you borrowed. r is the interest rate in percentage and t is the time.
+
+### S-3: Solution
+
+```python
+def compound_interest(principle, rate, time):
+	interest = principle * ((1 + rate / 100) ** time)
+	return interest
+
+principle = int(input("Money you borrowed: "))
+interest_rate = float(input("Interest Rate: "))
+time = float(input("Overall Duration: "))
+
+total_due = compound_interest(principle, interest_rate, time)
+
+print("Interest Amount is:", total_due)
+```
+
+**[Try It:](/https://play.google.com/store/apps/details?id=com.learnprogramming.codecamp)**
+
+### S-4: Explanation
+Inside the function, just look into the power calculation. 
+
+**(1 + rate / 100)  time**
+
+Rest of the part should be easy for you. 
+
+### S-5: Take Away
+To apply the same power on multiple things, put them inside parentheses and then apply the power. 
+
+
+ 
+[![Next Page](assets/next-button.png)](Calculate-Grades.md)
+ 
+
+###### tags: `programmig-hero` `python` `float` `int` `math`

Computations/Gravitational-Force.md

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+## 6.4 Gravitational Force
+
+### S-1: The Problem
+Compute gravitational force between two objects. 
+
+### S-2: Hint
+The formula for gravitational force is 
+
+**F = G m1m2/r2**
+
+Here G is the gravitational constant. Its value is 6.673*10-11
+
+So, take three input from the users. The mass of the first object, the mass of the second object and the distance between them.  
+
+### S-3: Solution
+
+```python
+mass1 = float(input("First mass: "))
+mass2 = float(input("Second mass: "))
+ 
+r = float(input("Distance between the objects: "))
+ 
+G = 6.673*(10**-11)
+force =(G*mass1*mass2)/(r**2)
+ 
+print("The gravitational force is:", round(force, 5),"N")
+```
+ 
+**[Try It:](/https://play.google.com/store/apps/details?id=com.learnprogramming.codecamp)**
+
+### S-4: Explanation
+The calculation is simple. Only two things need to be learned from this. 
+
+**Have a look, how we wrote 6.673*10-11**
+
+> Also, note that while displaying the force, we used a round function. In the round function, we passed the force, the variable we want to display. Then we passed another parameter to tell, how many decimal points we want to display. 
+
+
+ 
+[![Next Page](assets/next-button.png)](Triangle-Area.md)
+ 
+
+###### tags: `programmig-hero` `python` `float` `int` `math`

Computations/Simple-Interest.md

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+## 6.1: Simple Interest 
+
+---
+
+### S-1: The Problem
+You borrowed $5000 for 2 years with 2% interest per year.
+Calculate the simple interest to know how much you have to pay?
+
+### S-2: Hint
+Just take amount, duration and interest rate. 
+
+You have to multiply these three. And, don’t forget: you have to convert percent to a fraction by dividing it by 100.
+
+### S-3: The Solution
+
+```python
+principle = int(input("Money you borrowed: "))
+interest_rate = float(input("Interest Rate: "))
+time = float(input("Overall Duration: "))
+
+# Calculates simple interest
+simple_interest = principle * (interest_rate/100) * time
+
+print("Simple interest is:", simple_interest)
+```
+
+**[Try It:](/https://play.google.com/store/apps/details?id=com.learnprogramming.codecamp)**
+
+### S-4: Explanation
+Read the code. I think you don’t need any extra explanation here. 
+
+ 
+[![Next Page](assets/next-button.png)](Math-Power.md)
+ 
+
+###### tags: `programmig-hero` `python` `float` `int` `math`
+
+ 
+[![Next Page](assets/next-button.png)](Complex-Interest.md)
+ 
+
+###### tags: `programmig-hero` `python` `float` `int` `math`

Computations/Triangle-Area.md

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+## 6.5 Triangle Area
+---
+
+### S-1: The Problem 
+Take three sides of a triangle. And then calculate the area of the triangle. 
+
+### S-2: How it works 
+To calculate the area of the triangle. First, calculate the half of the perimeter. Here perimeter is the sum of each side of the triangle.
+
+Let’s call it s. 
+
+Then you have to perform square root of the formula like below-
+
+```python
+s = (a+b+c)/2
+area = √(s(s-a)*(s-b)*(s-c))
+```
+
+### S-3: the code
+```python
+import math
+
+a = float(input('Enter first side: '))
+b = float(input('Enter second side: '))
+c = float(input('Enter third side: '))
+
+# calculate the semi-perimeter
+s = (a + b + c) / 2
+
+# calculate the area
+area = math.sqrt(s*(s-a)*(s-b)*(s-c))
+print('Area of your triangle is ', area)
+```
+**[Try It:](/https://play.google.com/store/apps/details?id=com.learnprogramming.codecamp)**
+
+### S-4: Explanation
+To calculate the square root. We used the math module. And call math.sqrt. 
+
+```python
+import math
+print ( math.sqrt(4) )
+```
+
+This will give you 2 as output.
+
+Similarly, math.sqrt(25) will give 5 as output.
+
+This is something new you have learned this time. 
+
+### S-5: Quiz
+
+1. How would you calculate the square root of a number. 
+2. Use math.square.root
+3. Use math.sqroot
+4. Use math.sqrt
+
+**The answer is: 3**
+
+### S-6: Take Away
+The math module has a lot of math-related functionalities. 
+
+
+ 
+[![Next Page](assets/next-button.png)](..README.md)
+ 
+
+###### tags: `programmig-hero` `python` `float` `int` `math`

Conversions/Celsius-to-Fahrenheit.md

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+## 4.2 Celsius to Fahrenheit
+
+### S-1: The problem
+Take the temperature in degrees Celsius and convert it to Fahrenheit.
+
+<details>
+ <summary><b>S-2: Click Here For Show Hints</b></summary>
+   <p>To convert degrees Celsius temperature to Fahrenheit, you have to multiply by 9 and divide by 5.
+   
+   And then, add 32.</p>
+ </details>
+
+Think for a second...How will you multiply a variable by 9 and then divide by 5? and then add 32. Can you do it without looking at the solution? 
+
+### S-3: The solution
+```python
+celsius = float(input("Enter temperature in degrees Celsius: "))
+ 
+fahrenheit = celsius*9/5+32
+ 
+print("Temperature in Fahrenheit:", fahrenheit)
+```
+ 
+**[Try It:](https://play.google.com/store/apps/details?id=com.learnprogramming.codecamp)**
+
+&nbsp;
+[![Next Page](../assets/next-button.png)](../README.md)
+&nbsp;
+
+###### tags: `programmig-hero` `python` `float` `int` `math`
+

Conversions/Decimal-to-binary-recursive.md

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+## 4.4: Decimal to Binary (recursive) 
+
+### S-1: The Problem
+Convert a decimal number to binary number using a recursive function. 
+<details>
+ <summary><b>S-3: Click Here For Show Hints</b></summary>
+   <p>After coding for a while, recursive will become fun. Until then, recursive functions might feel like confusing magic. 
+
+So, don’t worry if you felt confused. You are not alone. I am in the same condition as well.</p>
+ </details>
+
+### S-3: Recursive
+
+```python=
+def dec_to_binary(n):
+   if n > 1:
+       dec_to_binary(n//2)
+   print(n % 2,end = '')
+```
+
+### decimal number
+```python=
+num = int(input("Your decimal number: "))
+dec_to_binary(num)
+print(" ")
+```
+
+**[Try It:](/https://play.google.com/store/apps/details?id=com.learnprogramming.codecamp)**
+
+### S-4: Explanation
+The core part of the logic is simple. If the number is greater than 1, call the dec_to_binary function again. And, while calling, send the result of dividing operation as the input number. 
+
+If you remember, the while loop in the previous code problem is similar. In the while loop, we were going back to the next iteration with n = n//2
+
+Here we are calling the same function with the n//2
+
+In the previous code problem (iterative), we are putting the remainder in a list. Here, we are printing it right away. 
+
+While printing, we have one extra thing called end=''. 
+The purpose of end='' is to print the output in the same line. If you don’t add end='', every print output will be displayed in a new line. 
+
+
+### S-6: Take Away
+There are multiple ways to format the print string. Google it, when needed.
+
+
+&nbsp;
+[![Next Page](../assets/next-button.png)](../README.md)
+&nbsp;
+
+###### tags: `programmig-hero` `python` `float` `int` `math`