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0210. Course Schedule II.js
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// There are a total of n courses you have to take, labeled from 0 to n-1.
// Some courses may have prerequisites, for example to take course 0 you have to first take course 1, which is expressed as a pair: [0,1]
// Given the total number of courses and a list of prerequisite pairs, return the ordering of courses you should take to finish all courses.
// There may be multiple correct orders, you just need to return one of them. If it is impossible to finish all courses, return an empty array.
//
// Example 1:
//
// Input: 2, [[1,0]]
// Output: [0,1]
// Explanation: There are a total of 2 courses to take. To take course 1 you should have finished
// course 0. So the correct course order is [0,1].
//
// Example 2:
//
// Input: 4, [[1,0],[2,0],[3,1],[3,2]]
// Output: [0,1,2,3] or [0,2,1,3]
// Explanation: There are a total of 4 courses to take. To take course 3 you should have finished both
// courses 1 and 2. Both courses 1 and 2 should be taken after you finished course 0.
// So one correct course order is [0,1,2,3]. Another correct ordering is [0,2,1,3].
//
// Note:
//
// The input prerequisites is a graph represented by a list of edges, not adjacency matrices. Read more about how a graph is represented.
// You may assume that there are no duplicate edges in the input prerequisites.
/**
* @param {number} numCourses
* @param {number[][]} prerequisites
* @return {number[]}
*/
// Topological Sorting + BFS
// Similar
// 210. Course Schedule II
// 269. Alien Dictionary
const findOrder = (numCourses, prerequisites) => {
const inDegrees = Array(numCourses).fill(0);
for (const [v] of prerequisites) {
inDegrees[v]++;
}
const q = [];
for (let i = 0; i < inDegrees.length; i++) {
const degree = inDegrees[i];
if (degree === 0) q.push(i);
}
const res = [];
while (q.length) {
const u0 = q.shift();
numCourses--;
res.push(u0);
for (const [v, u] of prerequisites) {
if (u === u0) {
inDegrees[v]--;
if (inDegrees[v] === 0) q.push(v);
}
}
}
return numCourses === 0 ? res : [];
};