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Copy path315.Count-of-Smaller-Numbers-After-Self.java
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315.Count-of-Smaller-Numbers-After-Self.java
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// https://leetcode.com/problems/count-of-smaller-numbers-after-self/
//
// algorithms
// Hard (37.96%)
// Total Accepted: 74,842
// Total Submissions: 197,164
// beats 92.20% of java submissions
// 这道题开始一直没有用 mapping 数值来保存下标,res 一直加错索引,后面断点调试发现了
class Solution {
public List<Integer> countSmaller(int[] nums) {
int len = nums.length;
ArrayList<Integer> l = new ArrayList<>(len);
if (len == 0) {
return l;
}
int[] res = new int[len];
int[] mapping = new int[len];
for (int i = 0; i < len; i++) {
mapping[i] = i;
}
mergeSort(nums, mapping, res, 0, nums.length - 1);
for (int i = 0; i < len; i++) {
l.add(res[i]);
}
return l;
}
public void mergeSort(int[] nums, int[] mapping, int[] res, int head, int tail) {
if (tail == head) {
return;
}
int middle = head + (tail - head) / 2;
mergeSort(nums, mapping, res, head, middle);
mergeSort(nums, mapping, res,middle + 1, tail);
int l = head, r = middle + 1;
int[] tmp = new int[tail - head + 1];
int idx = 0;
while (l <= middle && r <= tail) {
if (nums[mapping[l]] > nums[mapping[r]]) {
tmp[idx] = mapping[l];
res[mapping[l]] += (tail - r + 1);
l++;
} else {
tmp[idx] = mapping[r];
r++;
}
idx++;
}
while (l <= middle) {
tmp[idx++] = mapping[l++];
}
while (r <= tail) {
tmp[idx++] = mapping[r++];
}
for (int i = head; i <= tail; i++) {
mapping[i] = tmp[i - head];
}
}
}