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Create Day-31_Find_minimum_in_rotated_sorted_array.py
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# Linear Search - O(N)
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# Binary Search - O(logN)
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class Solution:
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def findMin(self, nums: List[int]) -> int:
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# Special cases
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# If only one element
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if len(nums) == 1:
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return nums[0]
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# If not rotated. How do we know ? If nums[0] < nums[n-1]
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if nums[0] < nums[-1]:
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return nums[0]
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# Binary Search
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low, high = 0, len(nums) - 1
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while low <= high:
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mid = (low + high)//2
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if nums[mid] < nums[low]:
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# Check for inflection point on the left side
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high = mid - 1
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else:
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# Check for inflection point on the right side
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low = mid + 1
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if nums[mid] > nums[mid+1]:
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return nums[mid+1]
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if nums[mid] < nums[mid - 1]:
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return nums[mid]

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