DFS of Graph

Easy

You are given a connected undirected graph. Perform a Depth First Traversal of the graph.
Note: Use a recursive approach to find the DFS traversal of the graph starting from the 0th vertex from left to right according to the graph.

Example 1:

Input: V = 5 , adj = [[2,3,1] , [0], [0,4], [0], [2]]

Output: 0 2 4 3 1
Explanation: 
0 is connected to 2, 3, 1.
1 is connected to 0.
2 is connected to 0 and 4.
3 is connected to 0.
4 is connected to 2.
so starting from 0, it will go to 2 then 4,
and then 3 and 1.
Thus dfs will be 0 2 4 3 1.

Example 2:

Input: V = 4, adj = [[1,3], [2,0], [1], [0]]

Output: 0 1 2 3
Explanation:
0 is connected to 1 , 3.
1 is connected to 0, 2. 
2 is connected to 1.
3 is connected to 0. 
so starting from 0, it will go to 1 then 2
then back to 0 then 0 to 3
thus dfs will be 0 1 2 3. 

Your task:
You don't need to read input or print anything. Your task is to complete the function dfsOfGraph() which takes the integer V denoting the number of vertices and adjacency list as input parameters and returns a list containing the DFS traversal of the graph starting from the 0th vertex from left to right according to the graph.

Expected Time Complexity: O(V + E)
Expected Auxiliary Space: O(V)

Constraints:
1 ≤ V, E ≤ 10⁴