Given the root
of a binary tree, return the inorder traversal of its nodes' values.
Example 1:
Input: root = [1,null,2,3] Output: [1,3,2]
Example 2:
Input: root = [] Output: []
Example 3:
Input: root = [1] Output: [1]
Constraints:
- The number of nodes in the tree is in the range
[0, 100]
. -100 <= Node.val <= 100
Follow up: Recursive solution is trivial, could you do it iteratively?
Time Submitted | Status | Runtime | Memory | Language |
---|---|---|---|---|
08/17/2022 13:55 | Accepted | 6 ms | 8.4 MB | cpp |
08/30/2021 11:50 | Accepted | 0 ms | 10.4 MB | cpp |
08/13/2021 14:31 | Accepted | 0 ms | 10.2 MB | cpp |
08/13/2021 14:26 | Wrong Answer | N/A | N/A | cpp |