Simple_Website_Watcher

Check for updates on a website and notify by email or SMS

Requirements

How to use it

Read the tutorial and get a phone number with SMS on Twilio website.
Edit the Information class with your personal information to send the emails and SMS:

class Information():

    # Website Info
    URL = '<WEBSITE URL>'

    # Email Info
    FROM_EMAIL_LOGIN = 'XXXXXXX@hotmail.com'
    FROM_EMAIL_PASSW = '########'
    TO_EMAIL_LOGIN = 'XXXXXXX@hotmail.com'
    TO_EMAIL_TITLE = 'Warning: Website Updated'

    # SMS
    ACCOUNT_SID = '<TWILIO ACCOUNT_SID>'
    AUTH_TOKEN = '<TWILIO AUTH_TOKEN>'
    SMS_BODY = f'{URL} Updated'
    SMS_FROM = '<TWILIO PHONE NUMBER>'
    SMS_TO = '<YOUR PHONE NUMBER>'

If your email isn't a @hotmail.com, you will need to change the host variable in Notification class (look at the table below for your specific host).

class Notification(Site_watcher):

    def send_email(self):
        yag = yagmail.SMTP(Information.FROM_EMAIL_LOGIN,
                           Information.FROM_EMAIL_PASSW,
                           host='smtp-mail.outlook.com', port=587,
                           smtp_starttls=True, smtp_ssl=False)

Port 587 is a common port for most of SMTP servers, however some may have different ports (like 465).

This table from Automate Boring Stuff with Python summarizes the majority of servers:

Provider	SMTP server domain name
Gmail	smtp.gmail.com
Outlook.com/Hotmail.com	smtp-mail.outlook.com
Yahoo Mail	smtp.mail.yahoo.com
AT&T	smpt.mail.att.net (port 465)
Comcast	smtp.comcast.net
Verizon	smtp.verizon.net (port 465)

Warning

This is a very simple website watcher so be careful to not publish your private information online. Some emails will block this kind of activity, then you should confirm thats you.

License

luiseduardobr1/Simple_Website_Watcher

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