@eachrow over a range?

[untoreh]

If I do this:

@eachrow df[start:stop, :] ...

It works but the row index always starts from one.
Also @eachrow! doesn't operate on the same df since the indexing copies, and using a view gives error:

dfv = @view df[start:stop, :]
@eachrow! dfv ...
# ERROR: MethodError: no method matching transform!(::SubDataFrame{DataFrame, DataFrames.Index, UnitRange{Int64}})

[pdeffebach]

Can you try that second example on the latest version of DataFrames? 1.3.

I agree there could be some interesting design possibilities here. Check on 1.3 to see where we can start from.