matplotlib styles - setting a legend's background color?

[jclevesque]

Is there a way to change a legend's background color using styles (or equivalently, matplotlib rcParams)?

Say I set the axes background colors to grey, and I want my legend to pop out a bit more. I can set the axes background in my style, but I can't seem to find a way to do it for the legend.

import matplotlib.pyplot as plt
plt.style.use('mystyle')
plt.plot(np.random.sample(10), label='test')
legend = plt.legend()

# how do I automate these two lines
frame = legend.get_frame()
frame.set_facecolor('1')

plt.show()

mystyle.mplstyle :

axes.facecolor: E5E5E5
axes.edgecolor: white
axes.grid: True

xtick.color: 555555
xtick.direction: out

ytick.color: 555555
ytick.direction: out

grid.color: white
grid.linestyle: -    # solid line

figure.facecolor: white
figure.edgecolor: 0.50

[jclevesque]

Just found issue #3785

[WeatherGod]

You are in luck. We have just today merged #4193, which would allow you to
set a value of "inherit" to legend.facecolor and legend.edgecolor.

On Mon, Apr 20, 2015 at 11:43 AM, Julien-Charles Lévesque <
notifications@github.com> wrote:

Is there a way to change a legend's background color using styles (or
equivalently, matplotlib rcParams)?

Say I set the axes background colors to grey, and I want my legend to pop
out a bit more. I can set the axes background in my style, but I can't seem
to find a way to do it for the legend.

import matplotlib.pyplot as plt
plt.style.use('mystyle')
plt.plot(np.random.sample(10), label='test')
legend = plt.legend()

how do I automate these two lines

frame = legend.get_frame()
frame.set_facecolor('1')

plt.show()

mystyle.mplstyle :

axes.facecolor: E5E5E5
axes.edgecolor: white
axes.grid: True

xtick.color: 555555
xtick.direction: out

ytick.color: 555555
ytick.direction: out

grid.color: white
grid.linestyle: - # solid line

figure.facecolor: white
figure.edgecolor: 0.50

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#4360.