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I expect bitsets to compare equal as long as for every bit n in the allowed range (find bitset1 n) = (find bitset2 n).
Strict equality could compare the implementation details, but it doesn't seem useful at a glance, so I would vote it to also behave same as normal equality.
Platform version Red 0.6.5 for Windows built 17-Feb-2024/10:32:56+03:00 commit #58b8f89
The text was updated successfully, but these errors were encountered:
Describe the bug
Also related: #614 #5480
To reproduce
Expected behavior
I expect bitsets to compare equal as long as for every bit
n
in the allowed range(find bitset1 n) = (find bitset2 n)
.Strict equality could compare the implementation details, but it doesn't seem useful at a glance, so I would vote it to also behave same as normal equality.
Platform version
Red 0.6.5 for Windows built 17-Feb-2024/10:32:56+03:00 commit #58b8f89
The text was updated successfully, but these errors were encountered: