/
_linprog.py
956 lines (821 loc) · 34.7 KB
/
_linprog.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
170
171
172
173
174
175
176
177
178
179
180
181
182
183
184
185
186
187
188
189
190
191
192
193
194
195
196
197
198
199
200
201
202
203
204
205
206
207
208
209
210
211
212
213
214
215
216
217
218
219
220
221
222
223
224
225
226
227
228
229
230
231
232
233
234
235
236
237
238
239
240
241
242
243
244
245
246
247
248
249
250
251
252
253
254
255
256
257
258
259
260
261
262
263
264
265
266
267
268
269
270
271
272
273
274
275
276
277
278
279
280
281
282
283
284
285
286
287
288
289
290
291
292
293
294
295
296
297
298
299
300
301
302
303
304
305
306
307
308
309
310
311
312
313
314
315
316
317
318
319
320
321
322
323
324
325
326
327
328
329
330
331
332
333
334
335
336
337
338
339
340
341
342
343
344
345
346
347
348
349
350
351
352
353
354
355
356
357
358
359
360
361
362
363
364
365
366
367
368
369
370
371
372
373
374
375
376
377
378
379
380
381
382
383
384
385
386
387
388
389
390
391
392
393
394
395
396
397
398
399
400
401
402
403
404
405
406
407
408
409
410
411
412
413
414
415
416
417
418
419
420
421
422
423
424
425
426
427
428
429
430
431
432
433
434
435
436
437
438
439
440
441
442
443
444
445
446
447
448
449
450
451
452
453
454
455
456
457
458
459
460
461
462
463
464
465
466
467
468
469
470
471
472
473
474
475
476
477
478
479
480
481
482
483
484
485
486
487
488
489
490
491
492
493
494
495
496
497
498
499
500
501
502
503
504
505
506
507
508
509
510
511
512
513
514
515
516
517
518
519
520
521
522
523
524
525
526
527
528
529
530
531
532
533
534
535
536
537
538
539
540
541
542
543
544
545
546
547
548
549
550
551
552
553
554
555
556
557
558
559
560
561
562
563
564
565
566
567
568
569
570
571
572
573
574
575
576
577
578
579
580
581
582
583
584
585
586
587
588
589
590
591
592
593
594
595
596
597
598
599
600
601
602
603
604
605
606
607
608
609
610
611
612
613
614
615
616
617
618
619
620
621
622
623
624
625
626
627
628
629
630
631
632
633
634
635
636
637
638
639
640
641
642
643
644
645
646
647
648
649
650
651
652
653
654
655
656
657
658
659
660
661
662
663
664
665
666
667
668
669
670
671
672
673
674
675
676
677
678
679
680
681
682
683
684
685
686
687
688
689
690
691
692
693
694
695
696
697
698
699
700
701
702
703
704
705
706
707
708
709
710
711
712
713
714
715
716
717
718
719
720
721
722
723
724
725
726
727
728
729
730
731
732
733
734
735
736
737
738
739
740
741
742
743
744
745
746
747
748
749
750
751
752
753
754
755
756
757
758
759
760
761
762
763
764
765
766
767
768
769
770
771
772
773
774
775
776
777
778
779
780
781
782
783
784
785
786
787
788
789
790
791
792
793
794
795
796
797
798
799
800
801
802
803
804
805
806
807
808
809
810
811
812
813
814
815
816
817
818
819
820
821
822
823
824
825
826
827
828
829
830
831
832
833
834
835
836
837
838
839
840
841
842
843
844
845
846
847
848
849
850
851
852
853
854
855
856
857
858
859
860
861
862
863
864
865
866
867
868
869
870
871
872
873
874
875
876
877
878
879
880
881
882
883
884
885
886
887
888
889
890
891
892
893
894
895
896
897
898
899
900
901
902
903
904
905
906
907
908
909
910
911
912
913
914
915
916
917
918
919
920
921
922
923
924
925
926
927
928
929
930
931
932
933
934
935
936
937
938
939
940
941
942
943
944
945
946
947
948
949
950
951
952
953
954
955
956
"""
A top-level linear programming interface. Currently this interface only
solves linear programming problems via the Simplex Method.
.. versionadded:: 0.15.0
Functions
---------
.. autosummary::
:toctree: generated/
linprog
linprog_verbose_callback
linprog_terse_callback
"""
from __future__ import division, print_function, absolute_import
import numpy as np
from scipy.lib._numpy_compat import count_nonzero as _count_nonzero
from .optimize import OptimizeResult, _check_unknown_options
__all__ = ['linprog', 'linprog_verbose_callback', 'linprog_terse_callback']
__docformat__ = "restructuredtext en"
def linprog_verbose_callback(xk, **kwargs):
"""
A sample callback function demonstrating the linprog callback interface.
This callback produces detailed output to sys.stdout before each iteration
and after the final iteration of the simplex algorithm.
Parameters
----------
xk : array_like
The current solution vector.
**kwargs : dict
A dictionary containing the following parameters:
tableau : array_like
The current tableau of the simplex algorithm.
Its structure is defined in _solve_simplex.
phase : int
The current Phase of the simplex algorithm (1 or 2)
nit : int
The current iteration number.
pivot : tuple(int, int)
The index of the tableau selected as the next pivot,
or nan if no pivot exists
basis : array(int)
A list of the current basic variables.
Each element contains the name of a basic variable and its value.
complete : bool
True if the simplex algorithm has completed
(and this is the final call to callback), otherwise False.
"""
tableau = kwargs["tableau"]
nit = kwargs["nit"]
pivrow, pivcol = kwargs["pivot"]
phase = kwargs["phase"]
basis = kwargs["basis"]
complete = kwargs["complete"]
saved_printoptions = np.get_printoptions()
np.set_printoptions(linewidth=500,
formatter={'float':lambda x: "{: 12.4f}".format(x)})
if complete:
print("--------- Iteration Complete - Phase {:d} -------\n".format(phase))
print("Tableau:")
elif nit == 0:
print("--------- Initial Tableau - Phase {:d} ----------\n".format(phase))
else:
print("--------- Iteration {:d} - Phase {:d} --------\n".format(nit, phase))
print("Tableau:")
if nit >= 0:
print("" + str(tableau) + "\n")
if not complete:
print("Pivot Element: T[{:.0f}, {:.0f}]\n".format(pivrow, pivcol))
print("Basic Variables:", basis)
print()
print("Current Solution:")
print("x = ", xk)
print()
print("Current Objective Value:")
print("f = ", -tableau[-1, -1])
print()
np.set_printoptions(**saved_printoptions)
def linprog_terse_callback(xk, **kwargs):
"""
A sample callback function demonstrating the linprog callback interface.
This callback produces brief output to sys.stdout before each iteration
and after the final iteration of the simplex algorithm.
Parameters
----------
xk : array_like
The current solution vector.
**kwargs : dict
A dictionary containing the following parameters:
tableau : array_like
The current tableau of the simplex algorithm.
Its structure is defined in _solve_simplex.
vars : tuple(str, ...)
Column headers for each column in tableau.
"x[i]" for actual variables, "s[i]" for slack surplus variables,
"a[i]" for artificial variables, and "RHS" for the constraint
RHS vector.
phase : int
The current Phase of the simplex algorithm (1 or 2)
nit : int
The current iteration number.
pivot : tuple(int, int)
The index of the tableau selected as the next pivot,
or nan if no pivot exists
basics : list[tuple(int, float)]
A list of the current basic variables.
Each element contains the index of a basic variable and
its value.
complete : bool
True if the simplex algorithm has completed
(and this is the final call to callback), otherwise False.
"""
nit = kwargs["nit"]
if nit == 0:
print("Iter: X:")
print("{: <5d} ".format(nit), end="")
print(xk)
def _pivot_col(T, tol=1.0E-12, bland=False):
"""
Given a linear programming simplex tableau, determine the column
of the variable to enter the basis.
Parameters
----------
T : 2D ndarray
The simplex tableau.
tol : float
Elements in the objective row larger than -tol will not be considered
for pivoting. Nominally this value is zero, but numerical issues
cause a tolerance about zero to be necessary.
bland : bool
If True, use Bland's rule for selection of the column (select the
first column with a negative coefficient in the objective row,
regardless of magnitude).
Returns
-------
status: bool
True if a suitable pivot column was found, otherwise False.
A return of False indicates that the linear programming simplex
algorithm is complete.
col: int
The index of the column of the pivot element.
If status is False, col will be returned as nan.
"""
ma = np.ma.masked_where(T[-1, :-1] >= -tol, T[-1, :-1], copy=False)
if ma.count() == 0:
return False, np.nan
if bland:
return True, np.where(ma.mask == False)[0][0]
return True, np.ma.where(ma == ma.min())[0][0]
def _pivot_row(T, pivcol, phase, tol=1.0E-12):
"""
Given a linear programming simplex tableau, determine the row for the
pivot operation.
Parameters
----------
T : 2D ndarray
The simplex tableau.
pivcol : int
The index of the pivot column.
phase : int
The phase of the simplex algorithm (1 or 2).
tol : float
Elements in the pivot column smaller than tol will not be considered
for pivoting. Nominally this value is zero, but numerical issues
cause a tolerance about zero to be necessary.
Returns
-------
status: bool
True if a suitable pivot row was found, otherwise False. A return
of False indicates that the linear programming problem is unbounded.
row: int
The index of the row of the pivot element. If status is False, row
will be returned as nan.
"""
if phase == 1:
k = 2
else:
k = 1
ma = np.ma.masked_where(T[:-k, pivcol] <= tol, T[:-k, pivcol], copy=False)
if ma.count() == 0:
return False, np.nan
mb = np.ma.masked_where(T[:-k, pivcol] <= tol, T[:-k, -1], copy=False)
q = mb / ma
return True, np.ma.where(q == q.min())[0][0]
def _solve_simplex(T, n, basis, maxiter=1000, phase=2, callback=None,
tol=1.0E-12, nit0=0, bland=False):
"""
Solve a linear programming problem in "standard maximization form" using
the Simplex Method.
Minimize :math:`f = c^T x`
subject to
.. math::
Ax = b
x_i >= 0
b_j >= 0
Parameters
----------
T : array_like
A 2-D array representing the simplex T corresponding to the
maximization problem. It should have the form:
[[A[0, 0], A[0, 1], ..., A[0, n_total], b[0]],
[A[1, 0], A[1, 1], ..., A[1, n_total], b[1]],
.
.
.
[A[m, 0], A[m, 1], ..., A[m, n_total], b[m]],
[c[0], c[1], ..., c[n_total], 0]]
for a Phase 2 problem, or the form:
[[A[0, 0], A[0, 1], ..., A[0, n_total], b[0]],
[A[1, 0], A[1, 1], ..., A[1, n_total], b[1]],
.
.
.
[A[m, 0], A[m, 1], ..., A[m, n_total], b[m]],
[c[0], c[1], ..., c[n_total], 0],
[c'[0], c'[1], ..., c'[n_total], 0]]
for a Phase 1 problem (a Problem in which a basic feasible solution is
sought prior to maximizing the actual objective. T is modified in
place by _solve_simplex.
n : int
The number of true variables in the problem.
basis : array
An array of the indices of the basic variables, such that basis[i]
contains the column corresponding to the basic variable for row i.
Basis is modified in place by _solve_simplex
maxiter : int
The maximum number of iterations to perform before aborting the
optimization.
phase : int
The phase of the optimization being executed. In phase 1 a basic
feasible solution is sought and the T has an additional row representing
an alternate objective function.
callback : callable
If a callback function is provided, it will be called within each
iteration of the simplex algorithm. The callback must have the
signature `callback(xk, **kwargs)` where xk is the current solution
vector and kwargs is a dictionary containing the following::
"T" : The current Simplex algorithm T
"nit" : The current iteration.
"pivot" : The pivot (row, column) used for the next iteration.
"phase" : Whether the algorithm is in Phase 1 or Phase 2.
"basis" : The indices of the columns of the basic variables.
tol : float
The tolerance which determines when a solution is "close enough" to
zero in Phase 1 to be considered a basic feasible solution or close
enough to positive to to serve as an optimal solution.
nit0 : int
The initial iteration number used to keep an accurate iteration total
in a two-phase problem.
bland : bool
If True, choose pivots using Bland's rule [3]. In problems which
fail to converge due to cycling, using Bland's rule can provide
convergence at the expense of a less optimal path about the simplex.
Returns
-------
res : OptimizeResult
The optimization result represented as a ``OptimizeResult`` object.
Important attributes are: ``x`` the solution array, ``success`` a
Boolean flag indicating if the optimizer exited successfully and
``message`` which describes the cause of the termination. Possible
values for the ``status`` attribute are:
0 : Optimization terminated successfully
1 : Iteration limit reached
2 : Problem appears to be infeasible
3 : Problem appears to be unbounded
See `OptimizeResult` for a description of other attributes.
"""
nit = nit0
complete = False
solution = np.zeros(T.shape[1]-1, dtype=np.float64)
if phase == 1:
m = T.shape[0]-2
elif phase == 2:
m = T.shape[0]-1
else:
raise ValueError("Argument 'phase' to _solve_simplex must be 1 or 2")
while not complete:
# Find the pivot column
pivcol_found, pivcol = _pivot_col(T, tol, bland)
if not pivcol_found:
pivcol = np.nan
pivrow = np.nan
status = 0
complete = True
else:
# Find the pivot row
pivrow_found, pivrow = _pivot_row(T, pivcol, phase, tol)
if not pivrow_found:
status = 3
complete = True
if callback is not None:
solution[:] = 0
solution[basis[:m]] = T[:m, -1]
callback(solution[:n], **{"tableau": T,
"phase":phase,
"nit":nit,
"pivot":(pivrow, pivcol),
"basis":basis,
"complete": complete and phase == 2})
if not complete:
if nit >= maxiter:
# Iteration limit exceeded
status = 1
complete = True
else:
# variable represented by pivcol enters
# variable in basis[pivrow] leaves
basis[pivrow] = pivcol
pivval = T[pivrow][pivcol]
T[pivrow, :] = T[pivrow, :] / pivval
for irow in range(T.shape[0]):
if irow != pivrow:
T[irow, :] = T[irow, :] - T[pivrow, :]*T[irow, pivcol]
nit += 1
return nit, status
def _linprog_simplex(c, A_ub=None, b_ub=None, A_eq=None, b_eq=None,
bounds=None, maxiter=1000, disp=False, callback=None,
tol=1.0E-12, bland=False, **unknown_options):
"""
Solve the following linear programming problem via a two-phase
simplex algorithm.
maximize: c^T * x
subject to: A_ub * x <= b_ub
A_eq * x == b_eq
Parameters
----------
c : array_like
Coefficients of the linear objective function to be maximized.
A_ub :
2-D array which, when matrix-multiplied by x, gives the values of the
upper-bound inequality constraints at x.
b_ub : array_like
1-D array of values representing the upper-bound of each inequality
constraint (row) in A_ub.
A_eq : array_like
2-D array which, when matrix-multiplied by x, gives the values of the
equality constraints at x.
b_eq : array_like
1-D array of values representing the RHS of each equality constraint
(row) in A_eq.
bounds : array_like
The bounds for each independent variable in the solution, which can take
one of three forms::
None : The default bounds, all variables are non-negative.
(lb, ub) : If a 2-element sequence is provided, the same
lower bound (lb) and upper bound (ub) will be applied
to all variables.
[(lb_0, ub_0), (lb_1, ub_1), ...] : If an n x 2 sequence is provided,
each variable x_i will be bounded by lb[i] and ub[i].
Infinite bounds are specified using -np.inf (negative)
or np.inf (positive).
maxiter : int
The maximum number of iterations to perform.
disp : bool
If True, print exit status message to sys.stdout
callback : callable
If a callback function is provide, it will be called within each
iteration of the simplex algorithm. The callback must have the
signature `callback(xk, **kwargs)` where xk is the current solution
vector and kwargs is a dictionary containing the following::
"tableau" : The current Simplex algorithm tableau
"nit" : The current iteration.
"pivot" : The pivot (row, column) used for the next iteration.
"phase" : Whether the algorithm is in Phase 1 or Phase 2.
"bv" : A structured array containing a string representation of each
basic variable and its current value.
tol : float
The tolerance which determines when a solution is "close enough" to zero
in Phase 1 to be considered a basic feasible solution or close enough
to positive to to serve as an optimal solution.
bland : bool
If True, use Bland's anti-cycling rule [3] to choose pivots to
prevent cycling. If False, choose pivots which should lead to a
converged solution more quickly. The latter method is subject to
cycling (non-convergence) in rare instances.
Returns
-------
A scipy.optimize.OptimizeResult consisting of the following fields::
x : ndarray
The independent variable vector which optimizes the linear
programming problem.
slack : ndarray
The values of the slack variables. Each slack variable corresponds
to an inequality constraint. If the slack is zero, then the
corresponding constraint is active.
success : bool
Returns True if the algorithm succeeded in finding an optimal
solution.
status : int
An integer representing the exit status of the optimization::
0 : Optimization terminated successfully
1 : Iteration limit reached
2 : Problem appears to be infeasible
3 : Problem appears to be unbounded
nit : int
The number of iterations performed.
message : str
A string descriptor of the exit status of the optimization.
Examples
--------
Consider the following problem:
Minimize: f = -1*x[0] + 4*x[1]
Subject to: -3*x[0] + 1*x[1] <= 6
1*x[0] + 2*x[1] <= 4
x[1] >= -3
where: -inf <= x[0] <= inf
This problem deviates from the standard linear programming problem. In
standard form, linear programming problems assume the variables x are
non-negative. Since the variables don't have standard bounds where
0 <= x <= inf, the bounds of the variables must be explicitly set.
There are two upper-bound constraints, which can be expressed as
dot(A_ub, x) <= b_ub
The input for this problem is as follows:
>>> c = [-1, 4]
>>> A = [[-3, 1], [1, 2]]
>>> b = [6, 4]
>>> x0_bnds = (None, None)
>>> x1_bnds = (-3, None)
>>> res = linprog(c, A, b, bounds=(x0_bnds, x1_bnds), options={"disp":True})
>>> print(res)
Optimization terminated successfully.
Current function value: 11.428571
Iterations: 2
status: 0
success: True
fun: 11.428571428571429
x: array([-1.14285714, 2.57142857])
slack: array([], dtype=np.float64)
message: 'Optimization terminated successfully.'
nit: 2
References
----------
.. [1] Dantzig, George B., Linear programming and extensions. Rand
Corporation Research Study Princeton Univ. Press, Princeton, NJ, 1963
.. [2] Hillier, S.H. and Lieberman, G.J. (1995), "Introduction to
Mathematical Programming", McGraw-Hill, Chapter 4.
.. [3] Bland, Robert G. New finite pivoting rules for the simplex method.
Mathematics of Operations Research (2), 1977: pp. 103-107.
"""
_check_unknown_options(unknown_options)
status = 0
messages = {0: "Optimization terminated successfully.",
1: "Iteration limit reached.",
2: "Optimzation failed. Unable to find a feasible"
" starting point.",
3: "Optimization failed. The problem appears to be unbounded.",
4: "Optimization failed. Singular matrix encountered."}
have_floor_variable = False
cc = np.asarray(c)
# The initial value of the objective function element in the tableau
f0 = 0
# The number of variables as given by c
n = len(c)
# Convert the input arguments to arrays (sized to zero if not provided)
Aeq = np.asarray(A_eq) if A_eq is not None else np.empty([0, len(cc)])
Aub = np.asarray(A_ub) if A_ub is not None else np.empty([0, len(cc)])
beq = np.ravel(np.asarray(b_eq)) if b_eq is not None else np.empty([0])
bub = np.ravel(np.asarray(b_ub)) if b_ub is not None else np.empty([0])
# Analyze the bounds and determine what modifications to me made to
# the constraints in order to accommodate them.
L = np.zeros(n, dtype=np.float64)
U = np.ones(n, dtype=np.float64)*np.inf
if bounds is None or len(bounds) == 0:
pass
elif len(bounds) == 2 and not hasattr(bounds[0], '__len__'):
# All bounds are the same
L = np.asarray(n*[bounds[0]], dtype=np.float64)
U = np.asarray(n*[bounds[1]], dtype=np.float64)
else:
if len(bounds) != n:
status = -1
message = ("Invalid input for linprog with method = 'simplex'. "
"Length of bounds is inconsistent with the length of c")
else:
try:
for i in range(n):
if len(bounds[i]) != 2:
raise IndexError()
L[i] = bounds[i][0] if bounds[i][0] is not None else -np.inf
U[i] = bounds[i][1] if bounds[i][1] is not None else np.inf
except IndexError:
status = -1
message = ("Invalid input for linprog with "
"method = 'simplex'. bounds must be a n x 2 "
"sequence/array where n = len(c).")
if np.any(L == -np.inf):
# If any lower-bound constraint is a free variable
# add the first column variable as the "floor" variable which
# accommodates the most negative variable in the problem.
n = n + 1
L = np.concatenate([np.array([0]), L])
U = np.concatenate([np.array([np.inf]), U])
cc = np.concatenate([np.array([0]), cc])
Aeq = np.hstack([np.zeros([Aeq.shape[0], 1]), Aeq])
Aub = np.hstack([np.zeros([Aub.shape[0], 1]), Aub])
have_floor_variable = True
# Now before we deal with any variables with lower bounds < 0,
# deal with finite bounds which can be simply added as new constraints.
# Also validate bounds inputs here.
for i in range(n):
if(L[i] > U[i]):
status = -1
message = ("Invalid input for linprog with method = 'simplex'. "
"Lower bound %d is greater than upper bound %d" % (i, i))
if np.isinf(L[i]) and L[i] > 0:
status = -1
message = ("Invalid input for linprog with method = 'simplex'. "
"Lower bound may not be +infinity")
if np.isinf(U[i]) and U[i] < 0:
status = -1
message = ("Invalid input for linprog with method = 'simplex'. "
"Upper bound may not be -infinity")
if np.isfinite(L[i]) and L[i] > 0:
# Add a new lower-bound (negative upper-bound) constraint
Aub = np.vstack([Aub, np.zeros(n)])
Aub[-1, i] = -1
bub = np.concatenate([bub, np.array([-L[i]])])
L[i] = 0
if np.isfinite(U[i]):
# Add a new upper-bound constraint
Aub = np.vstack([Aub, np.zeros(n)])
Aub[-1, i] = 1
bub = np.concatenate([bub, np.array([U[i]])])
U[i] = np.inf
# Now find negative lower bounds (finite or infinite) which require a
# change of variables or free variables and handle them appropriately
for i in range(0, n):
if L[i] < 0:
if np.isfinite(L[i]) and L[i] < 0:
# Add a change of variables for x[i]
# For each row in the constraint matrices, we take the
# coefficient from column i in A,
# and subtract the product of that and L[i] to the RHS b
beq[:] = beq[:] - Aeq[:, i] * L[i]
bub[:] = bub[:] - Aub[:, i] * L[i]
# We now have a nonzero initial value for the objective
# function as well.
f0 = f0 - cc[i] * L[i]
else:
# This is an unrestricted variable, let x[i] = u[i] - v[0]
# where v is the first column in all matrices.
Aeq[:, 0] = Aeq[:, 0] - Aeq[:, i]
Aub[:, 0] = Aub[:, 0] - Aub[:, i]
cc[0] = cc[0] - cc[i]
if np.isinf(U[i]):
if U[i] < 0:
status = -1
message = ("Invalid input for linprog with "
"method = 'simplex'. Upper bound may not be -inf.")
# The number of upper bound constraints (rows in A_ub and elements in b_ub)
mub = len(bub)
# The number of equality constraints (rows in A_eq and elements in b_eq)
meq = len(beq)
# The total number of constraints
m = mub+meq
# The number of slack variables (one for each of the upper-bound constraints)
n_slack = mub
# The number of artificial variables (one for each lower-bound and equality
# constraint)
n_artificial = meq + _count_nonzero(bub < 0)
try:
Aub_rows, Aub_cols = Aub.shape
except ValueError:
raise ValueError("Invalid input. A_ub must be two-dimensional")
try:
Aeq_rows, Aeq_cols = Aeq.shape
except ValueError:
raise ValueError("Invalid input. A_eq must be two-dimensional")
if Aeq_rows != meq:
status = -1
message = ("Invalid input for linprog with method = 'simplex'. "
"The number of rows in A_eq must be equal "
"to the number of values in b_eq")
if Aub_rows != mub:
status = -1
message = ("Invalid input for linprog with method = 'simplex'. "
"The number of rows in A_ub must be equal "
"to the number of values in b_ub")
if Aeq_cols > 0 and Aeq_cols != n:
status = -1
message = ("Invalid input for linprog with method = 'simplex'. "
"Number of columns in A_eq must be equal "
"to the size of c")
if Aub_cols > 0 and Aub_cols != n:
status = -1
message = ("Invalid input for linprog with method = 'simplex'. "
"Number of columns in A_ub must be equal to the size of c")
if status != 0:
# Invalid inputs provided
raise ValueError(message)
# Create the tableau
T = np.zeros([m+2, n+n_slack+n_artificial+1])
# Insert objective into tableau
T[-2, :n] = cc
T[-2, -1] = f0
b = T[:-2, -1]
if meq > 0:
# Add Aeq to the tableau
T[:meq, :n] = Aeq
# Add beq to the tableau
b[:meq] = beq
if mub > 0:
# Add Aub to the tableau
T[meq:meq+mub, :n] = Aub
# At bub to the tableau
b[meq:meq+mub] = bub
# Add the slack variables to the tableau
np.fill_diagonal(T[meq:m, n:n+n_slack], 1)
# Further setup the tableau
# If a row corresponds to an equality constraint or a negative b (a lower
# bound constraint), then an artificial variable is added for that row.
# Also, if b is negative, first flip the signs in that constraint.
slcount = 0
avcount = 0
basis = np.zeros(m, dtype=int)
r_artificial = np.zeros(n_artificial, dtype=int)
for i in range(m):
if i < meq or b[i] < 0:
# basic variable i is in column n+n_slack+avcount
basis[i] = n+n_slack+avcount
r_artificial[avcount] = i
avcount += 1
if b[i] < 0:
b[i] *= -1
T[i, :-1] *= -1
T[i, basis[i]] = 1
T[-1, basis[i]] = 1
else:
# basic variable i is in column n+slcount
basis[i] = n+slcount
slcount += 1
# Make the artificial variables basic feasible variables by subtracting
# each row with an artificial variable from the Phase 1 objective
for r in r_artificial:
T[-1, :] = T[-1, :] - T[r, :]
nit1, status = _solve_simplex(T, n, basis, phase=1, callback=callback,
maxiter=maxiter, tol=tol, bland=bland)
# if pseudo objective is zero, remove the last row from the tableau and
# proceed to phase 2
if abs(T[-1, -1]) < tol:
# Remove the pseudo-objective row from the tableau
T = T[:-1, :]
# Remove the artificial variable columns from the tableau
T = np.delete(T, np.s_[n+n_slack:n+n_slack+n_artificial], 1)
else:
# Failure to find a feasible starting point
status = 2
if status != 0:
message = messages[status]
if disp:
print(message)
return OptimizeResult(x=np.nan, fun=-T[-1, -1], nit=nit1, status=status,
message=message, success=False)
# Phase 2
nit2, status = _solve_simplex(T, n, basis, maxiter=maxiter-nit1, phase=2,
callback=callback, tol=tol, nit0=nit1,
bland=bland)
solution = np.zeros(n+n_slack+n_artificial)
solution[basis[:m]] = T[:m, -1]
x = solution[:n]
slack = solution[n:n+n_slack]
# For those variables with finite negative lower bounds,
# reverse the change of variables
masked_L = np.ma.array(L, mask=np.isinf(L), fill_value=0.0).filled()
x = x + masked_L
# For those variables with infinite negative lower bounds,
# take x[i] as the difference between x[i] and the floor variable.
if have_floor_variable:
for i in range(1, n):
if np.isinf(L[i]):
x[i] -= x[0]
x = x[1:]
# Optimization complete at this point
obj = -T[-1, -1]
if status in (0, 1):
if disp:
print(messages[status])
print(" Current function value: {: <12.6f}".format(obj))
print(" Iterations: {:d}".format(nit2))
else:
if disp:
print(messages[status])
print(" Iterations: {:d}".format(nit2))
return OptimizeResult(x=x, fun=obj, nit=int(nit2), status=status, slack=slack,
message=messages[status], success=(status == 0))
def linprog(c, A_ub=None, b_ub=None, A_eq=None, b_eq=None,
bounds=None, method='simplex', callback=None,
options=None):
"""
Minimize a linear objective function subject to linear
equality and inequality constraints.
Linear Programming is intended to solve the following problem form:
Minimize: c^T * x
Subject to: A_ub * x <= b_ub
A_eq * x == b_eq
Parameters
----------
c : array_like
Coefficients of the linear objective function to be minimized.
A_ub :
2-D array which, when matrix-multiplied by x, gives the values of the
upper-bound inequality constraints at x.
b_ub : array_like
1-D array of values representing the upper-bound of each inequality
constraint (row) in A_ub.
A_eq : array_like
2-D array which, when matrix-multiplied by x, gives the values of the
equality constraints at x.
b_eq : array_like
1-D array of values representing the RHS of each equality constraint
(row) in A_eq.
bounds : sequence, optional
``(min, max)`` pairs for each element in ``x``, defining
the bounds on that parameter. Use None for one of ``min`` or
``max`` when there is no bound in that direction. By default
bounds are ``(0, None)`` (non-negative)
If a sequence containing a single tuple is provided, then ``min`` and
``max`` will be applied to all variables in the problem.
method : str, optional
Type of solver. At this time only 'simplex' is supported.
callback : callable, optional
If a callback function is provide, it will be called within each
iteration of the simplex algorithm. The callback must have the signature
`callback(xk, **kwargs)` where xk is the current solution vector
and kwargs is a dictionary containing the following::
"tableau" : The current Simplex algorithm tableau
"nit" : The current iteration.
"pivot" : The pivot (row, column) used for the next iteration.
"phase" : Whether the algorithm is in Phase 1 or Phase 2.
"basis" : The indices of the columns of the basic variables.
options : dict, optional
A dictionary of solver options. All methods accept the following
generic options:
maxiter : int
Maximum number of iterations to perform.
disp : bool
Set to True to print convergence messages.
For method-specific options, see `show_options('linprog')`.
Returns
-------
A `scipy.optimize.OptimizeResult` consisting of the following fields:
x : ndarray
The independent variable vector which optimizes the linear
programming problem.
slack : ndarray
The values of the slack variables. Each slack variable corresponds
to an inequality constraint. If the slack is zero, then the
corresponding constraint is active.
success : bool
Returns True if the algorithm succeeded in finding an optimal
solution.
status : int
An integer representing the exit status of the optimization::
0 : Optimization terminated successfully
1 : Iteration limit reached
2 : Problem appears to be infeasible
3 : Problem appears to be unbounded
nit : int
The number of iterations performed.
message : str
A string descriptor of the exit status of the optimization.
See Also
--------
show_options : Additional options accepted by the solvers
Notes
-----
This section describes the available solvers that can be selected by the
'method' parameter. The default method is *Simplex*.
Method *Simplex* uses the Simplex algorithm (as it relates to Linear
Programming, NOT the Nelder-Mead Simplex) [1]_, [2]_. This algorithm
should be reasonably reliable and fast.
.. versionadded:: 0.15.0
References
----------
.. [1] Dantzig, George B., Linear programming and extensions. Rand
Corporation Research Study Princeton Univ. Press, Princeton, NJ, 1963
.. [2] Hillier, S.H. and Lieberman, G.J. (1995), "Introduction to
Mathematical Programming", McGraw-Hill, Chapter 4.
.. [3] Bland, Robert G. New finite pivoting rules for the simplex method.
Mathematics of Operations Research (2), 1977: pp. 103-107.
Examples
--------
Consider the following problem:
Minimize: f = -1*x[0] + 4*x[1]
Subject to: -3*x[0] + 1*x[1] <= 6
1*x[0] + 2*x[1] <= 4
x[1] >= -3
where: -inf <= x[0] <= inf
This problem deviates from the standard linear programming problem.
In standard form, linear programming problems assume the variables x are
non-negative. Since the variables don't have standard bounds where
0 <= x <= inf, the bounds of the variables must be explicitly set.
There are two upper-bound constraints, which can be expressed as
dot(A_ub, x) <= b_ub
The input for this problem is as follows:
>>> c = [-1, 4]
>>> A = [[-3, 1], [1, 2]]
>>> b = [6, 4]
>>> x0_bounds = (None, None)
>>> x1_bounds = (-3, None)
>>> res = linprog(c, A_ub=A, b_ub=b, bounds=(x0_bounds, x1_bounds),
... options={"disp": True})
>>> print(res)
Optimization terminated successfully.
Current function value: -11.428571
Iterations: 2
status: 0
success: True
fun: -11.428571428571429
x: array([-1.14285714, 2.57142857])
message: 'Optimization terminated successfully.'
nit: 2
Note the actual objective value is 11.428571. In this case we minimized
the negative of the objective function.
"""
meth = method.lower()
if options is None:
options = {}
if meth == 'simplex':
return _linprog_simplex(c, A_ub=A_ub, b_ub=b_ub, A_eq=A_eq, b_eq=b_eq,
bounds=bounds, callback=callback, **options)
else:
raise ValueError('Unknown solver %s' % method)