You are given coins of different denominations and a total amount of money. Write a function to compute the number of combinations that make up that amount. You may assume that you have infinite number of each kind of coin.
Input: amount = 5, coins = [1, 2, 5] Output: 4 Explanation: there are four ways to make up the amount: 5=5 5=2+2+1 5=2+1+1+1 5=1+1+1+1+1
Input: amount = 3, coins = [2] Output: 0 Explanation: the amount of 3 cannot be made up just with coins of 2.
Input: amount = 10, coins = [10] Output: 1
You can assume that
0 <= amount <= 5000
1 <= coin <= 5000
- the number of coins is less than 500
- the answer is guaranteed to fit into signed 32-bit integer
- mine
- Java
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Dynamic Programming same as 70. Climbing Stairs.
Runtime: 3 ms, faster than 61.40%, Memory Usage: 36.9 MB, less than 75.53% of Java online submissions
// O(N*M)time O(N)space // N is amount, M is coins.length public int change(int amount, int[] coins) { int[] dp = new int[amount + 1]; dp[0] = 1; for(int coin : coins){ for(int j = coin; j <= amount; j++){ dp[j] += dp[j - coin]; } } return dp[amount]; }
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- Java