Wildcard routes?

[darrendb]

I'm using compoundjs to serve a RESTful api. I'm using an 'api' namespace to handle the REST calls like this:

    map.namespace('api', function (api) {
        api.get('targets',          'targets#index');
        api.get('targets/:id',      'targets#show');
        api.post('targets',         'targets#create');
        api.put('targets/:id',      'targets#update');
        api.delete('targets/:id',   'targets#destroy');
    });

On the client I am trying to use a simple backbone single-page app using pushState=true.

I'm having trouble figuring out the routing to keep node/express/compound from getting involved with anything other than the api. I've heard some mention of a wildcard route like '*' used in low-level express, maybe something like this:

app.get("*", function(req, res){
  res.sendfile('index.html');
});

When I tried doing something like map.get('', ...) and checked the route table with 'compound routes' it seemed that the '' was being treated as a string literal and it was trying to map a path like '/*', rather than recognizing it as a wildcard.

Is there some equivalent in railway-routes/compoundjs for this? Ultimately I want to preserve a request such as '/targets' or '/targets/3', server should just ignore or serve index.html and let backbone read the '/targets/3' and handle it with its client-side routing. I'm also concerned that using something like "res.sendfile('index.html')" would change the url before the client see's it, stripping the 'targets/3' before backbone can respond to it.

I found some similar Q&A on Stack Overflow but nothing that seemed to be specific to compoundjs or railway-routes.

Any suggestions, or documentation links would be greatly appreciated. Thanks!

[1602]

was being treated as a string literal and it was trying to map a path like '/*', rather than recognizing it as a wildcard.

not true.

if you specify

map.all('admin/*', 'ctl#test');

or

map.all('*', 'ctl#test');

depending on your needs you will be able to get all requests to posts.