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Chapter 11. Associative Containers

Exercise 11.1:

Describe the differences between a map and a vector.

map is an associative container whereas vector is a sequence container

Exercise 11.2:

Give an example of when each of list, vector, deque, map, and set might be most useful.

  • list : anytime when a doubly-linked list is required.
  • vector : anytime when a dynamic array is required.
  • deque : An answer from SO.
  • map : dictionary.
  • set : when to keep elements sorted and unique.

Exercise 11.5:

Explain the difference between a map and a set. When might you use one or the other?

A nice answer on SO

Exercise 11.6:

Explain the difference between a set and a list. When might you use one or the other?

list vs set

Exercise 11.15:

What are the mapped_type, key_type, and value_type of a map from int to vector< int >?

  • mapped_type : vector< int >
  • key_type : int
  • value_type : std::pair< const int, vector >

Exercise 11.16:

Using a map iterator write an expression that assigns a value to an element.

std::map<int, std::string> map;
map[25] = "Alan";
std::map<int, std::string>::iterator it = map.begin();
it->second = "Wang";

Exercise 11.17:

Assuming c is a multiset of strings and v is a vector of strings, explain the following calls. Indicate whether each call is legal:

copy(v.begin(), v.end(), inserter(c, c.end())); // legal
copy(v.begin(), v.end(), back_inserter(c)); // illegal, no `push_back` in `set`.
copy(c.begin(), c.end(), inserter(v, v.end())); // legal.
copy(c.begin(), c.end(), back_inserter(v)); // legal.

Exercise 11.18:

Write the type of map_it from the loop on page 430 without using auto or decltype.

std::map<std::string, size_t>::const_iterator;

Exercise 11.19:

Define a variable that you initialize by calling begin() on the multiset named bookstore from 11.2.2 (p. 425). Write the variable’s type without using auto or decltype.

using compareType = bool (*)(const Sales_data &lhs, const Sales_data &rhs);
std::multiset<Sales_data, compareType> bookstore(compareIsbn);
std::multiset<Sales_data, compareType>::iterator c_it = bookstore.begin();

Exercise 11.21:

Assuming word_count is a map from string to size_t and word is a string, explain the following loop:

while (cin >> word)
    ++word_count.insert({ word, 0 }).first->second;

This code can be explained like this pseudocode:

while reading into word
    if word_count has key word:
        word_count[word] += 1
    else:
        word_count[word] = 0
        word_count[word] += 1

Exercise 11.22:

Given a map<string, vector<int>>, write the types used as an argument and as the return value for the version of insert that inserts one element.

std::pair<std::string, std::vector<int>>    // argument
std::pair<std::map<std::string, std::vector<int>>::iterator, bool> // return

Exercise 11.34:

What would happen if we used the subscript operator instead of find in the transform function?

Say the code has been changed like below:

const string& transform(const string &s, const map<string, string> &m)
{
    return m[s];
}

The above code won't compile because the subscript operator might insert an element (when the element with the key s is not found), and we may use subscript only on a map that is not const.

Exercise 11.35:

In buildMap, what effect, if any, would there be from rewriting trans_map[key] = value.substr(1); as trans_map.insert({ key, value.substr(1) })?

  • use subscript operator: if a word does appear multiple times, our loops will put the last corresponding phrase into trans_map
  • use insert: if a word does appear multiple times, our loops will put the first corresponding phrase into trans_map

Exercise 11.36:

Our program does no checking on the validity of either input file. In particular, it assumes that the rules in the transformation file are all sensible. What would happen if a line in that file has a key, one space, and then the end of the line? Predict the behavior and then check it against your version of the program.

If so, a key-value pair is going to be added into the map: {key, ""}. As a result, any key would be replaced with empty string.

Exercise 11.37:

What are the advantages of an unordered container as compared to the ordered version of that container? What are the advantages of the ordered version?

A summary