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124 Binary Tree Maximum Path Sum.swift
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124 Binary Tree Maximum Path Sum.swift
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//
// 124 Binary Tree Maximum Path Sum.swift
// LeetCode-Solutions
//
// Created by Aleksandar Dinic on 02/05/2020.
// Copyright © 2020 Aleksandar Dinic. All rights reserved.
//
import Foundation
/// Source: https://leetcode.com/problems/binary-tree-maximum-path-sum/
class Solution {
/// Finds the maximum path sum in binary tree.
///
/// - Parameter root: Binary tree root.
///
/// - Returns: The maximum path sum.
///
/// - Complexity:
/// - time: O(n), where n is the number of nodes in binary tree.
/// - space: O(n), where n is the number of nodes in binary tree.
func maxPathSum(_ root: TreeNode?) -> Int {
guard let root = root else { return 0 }
var currMaxSum = Int.min
return max(maxPathSum(root, currMaxSum: &currMaxSum), currMaxSum)
}
private func maxPathSum(_ currNode: TreeNode?, currMaxSum: inout Int) -> Int {
guard let currNode = currNode else { return 0 }
let leftSum = max(maxPathSum(currNode.left, currMaxSum: &currMaxSum), 0)
let rightSum = max(maxPathSum(currNode.right, currMaxSum: &currMaxSum), 0)
currMaxSum = max(currNode.val + leftSum + rightSum, currMaxSum)
return max(leftSum, rightSum) + currNode.val
}
}
/// Provided Code
public class TreeNode {
public var val: Int
public var left: TreeNode?
public var right: TreeNode?
public init() {
self.val = 0
self.left = nil
self.right = nil
}
public init(_ val: Int) {
self.val = val
self.left = nil
self.right = nil
}
public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {
self.val = val
self.left = left
self.right = right
}
}