Impossible to set closed interval bounds explicitly with replace

[TimBergner]

Other than specified in the documentation it is impossible to set closed interval bounds explicitly with replace (at least I can't). When an interval boundary is closed, it remains closed unless you want to set it explicitly closed.
Example:

>>> i = P.closedopen(0, 2)
>>> i.replace()
[0,2)
>>> i.replace(left=P.CLOSED)
(0,2)
>>> i.replace(left=lambda v: P.CLOSED)
(0,2)
>>> i.replace(lower=1)
[1,2)

[AlexandreDecan]

Hello,

Could you tell me which version of portion you're using? When I execute your code snippet, I got:

>>> i = P.closedopen(0, 2)
>>> i.replace()
[0,2)
>>> i.replace(left=P.CLOSED)
[0,2)
>>> i.replace(left=lambda v: P.CLOSED)
[0,2)
>>> i.replace(lower=1)
[1,2)

... which is the desired behaviour.

Thanks

[TimBergner]

Ups. I can't reproduce the behavior now in a new instance of the IPython console. So I probably overwrote some variables or something like that.

Sorry for this issue! Even if the error was reproducible also after reloading portion while running the same iPython instance, I should have tested it again in a new instance - my fault.

Edit: It was the current version 2.1.2 but that probably doesn't matter anymore

[AlexandreDecan]

Don't worry ;) I'm glad it's not a new bug :-)