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import portion as p print(p.closed(0, 1).contains(p.empty()))
The above prints True, meaning than any interval contains the empty interval. Is that intended?
True
The text was updated successfully, but these errors were encountered:
I think it actually makes sense mathematically, I just wanted to make sure.
Sorry, something went wrong.
Hello,
You're right, the empty interval is contained in all (possibly empty as well) intervals, by definition.
Ok, thank you for clarifying!
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The above prints
True
, meaning than any interval contains the empty interval. Is that intended?The text was updated successfully, but these errors were encountered: