Is it possible to create a mapping per type discriminator?

[abstract-matters]

Something like this:

Mapper.CreateMap<DTO.Party, Party>();
Mapper.CreateMap<DTO.Party, SomeParty>().Where(source => source.PartyTypeDiscriminatorValue == 1);
Mapper.CreateMap<DTO.Party, SomeOtherParty>().Where(source => source.PartyTypeDiscriminatorValue == 2);

var party = new DTO.Party() { PartyTypeDiscriminatorValue = 2 };

var result = Mapper.Map<DTO.Party, Party>(party);

Assert.IsTrue(result is SomeOtherParty)

[jbogard]

I wonder if it could be part of the Include option?

[abstract-matters]

Yeah, having a Where() on the Include option would be excellent!
This would probably mean that the dictionary described in this post (below) should also contain the func for the discriminator. And the code for selecting the appropriate target type should evaluate the func.

http://stackoverflow.com/questions/8844959/mapping-derived-class-to-multiple-destinations-with-automapper

[ansydor]

it would be awesome. is there any solution for this situation right now?

[TylerCarlson1]

Added pull request to add this feature in #590. It's not a Where() but an IncludeOnSourceCondition() right now.

Also another note about this change. You will NOT be able to use this for projection at the moment. Entity Framework at least, because it doesn't support casting return types when you project.

[julealgon]

I just posted a question on StackOverflow related to the problems I'm having with mapping based on a property of the original model in a inheritance scenario.

http://stackoverflow.com/questions/30128551/how-do-i-leverage-constructusing-in-a-mapping-with-inherited-types

Jimmy, I'm sure my problem is related to this. Could you perhaps take a look at that and suggest some workaround?

[TylerCarlson1]

It is related to this and unfortunately there's nothing you can do with includes to make this work.
Issue is when you include one class the logic will then check every class that inherits from the base and use the highest derived ones for it. Regardless if you included it or not.

Fix for this issue in code shown here 3ed6d8a as part of #590

[lock]

This thread has been automatically locked since there has not been any recent activity after it was closed. Please open a new issue for related bugs.