-
Notifications
You must be signed in to change notification settings - Fork 0
/
InfixToPostfix.cpp
104 lines (87 loc) · 2.7 KB
/
InfixToPostfix.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
// Infix to Postfix
// Given an infix expression in the form of string str. Convert this infix expression to postfix expression.
// Infix expression: The expression of the form a op b. When an operator is in-between every pair of operands.
// Postfix expression: The expression of the form a b op. When an operator is followed for every pair of operands.
// ​Note: The order of precedence is: ^ greater than * equals to / greater than + equals to -.
// { Driver Code Starts
// C++ implementation to convert infix expression to postfix
#include<bits/stdc++.h>
using namespace std;
// } Driver Code Ends
class Solution
{
public:
int precedence(char c){
if(c == '^'){
return 3;
}else if(c == '*' || c == '/'){
return 2;
}else if(c == '+' || c == '-'){
return 1;
}else if(c == '('){
return 0;
}
}
//Function to convert an infix expression to a postfix expression.
string infixToPostfix(string s)
{
string res = "";
stack<char> st;
for(int i = 0; i < s.length(); i++)
{
if(isalnum(s[i])){
res += s[i];
}
else{
if(st.empty()){
st.push(s[i]);
}
else{
if(s[i] == '('){
st.push(s[i]);
}
else if(s[i] == ')')
{
while(st.top() != '('){
res += st.top();
st.pop();
}
st.pop();
}
else if(precedence(s[i]) > precedence(st.top())){
st.push(s[i]);
}
else if(precedence(s[i]) <= precedence(st.top())){
while(!st.empty() && precedence(s[i]) <= precedence(st.top())){
res += st.top();
st.pop();
}
st.push(s[i]);
}
}
}
}
while(!st.empty()){
res += st.top();
st.pop();
}
return res;
}
};
// { Driver Code Starts.
//Driver program to test above functions
int main()
{
int t;
cin>>t;
cin.ignore(INT_MAX, '\n');
while(t--)
{
string exp;
cin>>exp;
Solution ob;
cout<<ob.infixToPostfix(exp)<<endl;
}
return 0;
}
// } Driver Code Ends