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Task 2 Step 2 bitwise right-shift 12 instead of 16 line 39 of code in picture #8

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DanielC-33 opened this issue Nov 8, 2022 · 0 comments

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@DanielC-33
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Since we're looking to display hexadecimal digits, which are 4bits each, then wouldn't we shift by 12 bits instead of 16 for the 4th hex digit. I know it's not really important for this task because counter doesn't have this many bits, but I just thought it might be more correct, unless I'm wrong!

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