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sieve.py
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sieve.py
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import numpy as np
import cProfile
def simpleSieve(N): # Original sieve of Eratosthenes
P = []
for i in range(0, N + 1):
if i % 2 == 1: # Simple little even 'wheel'
P.append(1)
elif i == 2:
P.append(1) # Making sure two is prime
else:
P.append(0) # All evens are zero
P[1] = 0
m = 3 # Start with our first prime
n = m * m # looking starting ar its square
while n <= N:
if P[m] == 1:
while n <= N:
P[n] = 0 # m prime therefore n not
n = n + 2 * m # look at the next odd multiple of m; n = m(m + 2)
m = m + 2 # Next odd number
n = m * m
return P
def simpleSegSieve(N, delta, M): # sieve over a little interval segment
S = []
for i in range(0, delta + 1): # Setting all the number to be prime candidates
S.append(1)
for i in range(0, 2 - N): # In case we have 0 or 1, set them to 0
S[i] = 0
P = simpleSieve(M) # Use simple Era to get our sieving primes
for m in range(1, M + 1):
if P[m] == 1:
c = m * np.ceil(N / m) # a possible starting point for nPrime
NPrime = int(np.maximum(c, 2 * m))
while NPrime <= N + delta: # looking only in the interval
S[NPrime - N] = 0 # as nPrime is always some multiple of m prime, get rid of those positions
NPrime = NPrime + m # next multiple of m
return S
def subSegSieve(N, delta, M): # segmented sieve which calls only the primes it needs each time; "subroutine"
S = []
for i in range(0, delta + 1): # Prime candidates
S.append(1)
for i in range(0, 2 - N): # if 0 or 1 get rid
S[i] = 0
deltaPrime = int(np.floor(np.sqrt(M))) # an optimised interval length to find primes in; m' + delta'
MPrime = 1 # where does this prime interval start
while MPrime <= M:
P = simpleSegSieve(MPrime, deltaPrime, int(np.floor(np.sqrt(MPrime + deltaPrime)))) # getting them primes
for p in range(MPrime, int(np.minimum(M, MPrime + deltaPrime))+1):
if P[p - MPrime] == 1:
NPrime = int(np.maximum(p * np.ceil(N / p), 2 * p)) # setting n' as multiple of p
while NPrime <= N + delta: # composites in the desired interval
S[NPrime - N] = 0 # get rid of them
NPrime = NPrime + p # next prime multiple
MPrime = MPrime + deltaPrime + 1
return S
def segSieve(n, delta): # segmented optimal(?) sieve of Era
return subSegSieve(n, delta, int(np.floor(np.sqrt(n + delta)))) # optimal? maybe
def diophApprox(alpha, Q): # don't fucking ask me
b = int(np.floor(alpha))
p = b
q = 1
pMinus = 1
qMinus = 0
s = 1
while q <= Q:
if alpha == b:
return [p, -s * qMinus, q]
alpha = 1 / (alpha - b)
b = int(np.floor(alpha))
pPlus = b * p + pMinus
qPlus = b * q + qMinus
pMinus = p
qMinus = q
p = pPlus
q = qPlus
s = -s
return [int(pMinus), int(s * q), int(qMinus)]
def newSegSieve(n, delta, K): # segmented sieve with diophantine approx
SPrime = subSegSieve(n - delta, 2 * delta, K * delta) # get an approximation of all the primes; some false
S = []
n0 = n - delta
for j in range(-delta, delta + 1): # format is rather weird, is just to reflect that the interval is n +- delta
S.append(SPrime[j + delta]) # mirrors our earlier, perhaps faulty calc
M = int(np.floor(K * delta)) + 1
while M <= np.sqrt(n + delta): # gets a bit fucked, only passes if n large and delta smallish; I think
R = int(np.floor(M * np.sqrt(delta / (4 * n))))
m0 = M + R
a1 = n / (m0 * m0) % 1
a0 = n / m0 % 1
nu = 5 * delta / (4 * M)
aaq = diophApprox(a1, 2 * R)
c = int(np.floor(a0 * aaq[2] + 0.5))
k = int(np.floor(nu * aaq[2]))
for j in range(-k - 1, k + 2):
r0 = -aaq[1] * (c + j) % aaq[2]
kMin = int(np.ceil((M - m0 - r0) / aaq[2])) # begin work for dealing with the intersection
kMax = int(np.floor((M + 2 * R - m0 - r0) / aaq[2]))
intersection = []
for i in range(kMin, kMax + 1): # construct valid elements of the intersection
intersection.append(m0 + r0 + aaq[2] * i)
for m in intersection:
nPrime = int(np.floor((n + delta)) / m) * m # similar things again with setting n' multiple of m
if n - delta <= nPrime:
if nPrime <= n + delta:
if nPrime > m:
S[nPrime - n0] = 0 # if in interval and larger than m; kill it!
M = M + 2 * R + 1 # start point of new M interval; have to make it larger than M + 2R
return S
def subSegSieveFac(n, delta, M): # factorise numbers in interval using subroutine of segment sieve
F = []
Pi = []
for i in range(0, delta + 1):
F.append([]) # making a list of empty lists
Pi.append(1) # everything has 1 as a factor
deltaPrime = int(np.floor(np.sqrt(M))) # sub interval length for finding primes
MPrime = 1 # where that interval starts
while MPrime <= M: # only using primes less than M
P = simpleSegSieve(MPrime, deltaPrime, int(np.floor(np.sqrt(MPrime + deltaPrime)))) # get useful primes
for p in range(MPrime, MPrime + deltaPrime):
if P[p - MPrime] == 1:
k = 1 # which power of the prime?
d = p # start with the first power!
while d <= n + delta:
nPrime = d * int(np.ceil(n / d)) # same same bb
while nPrime <= n + delta:
if k == 1: # when the first power divides
F[nPrime - n].append([p, 1]) # add it to the list; [prime, power]
else:
for i in range(0, len(F[nPrime - n])): # finds the same prime in the list with small power
if F[nPrime - n][i][0] == p:
F[nPrime - n][i][1] = k # if same update power
Pi[nPrime - n] = p * Pi[nPrime - n] # add that prime factor to the divisor list
nPrime = nPrime + d # next multiple of prime power
k = k + 1 # next prime power
d = p * d # p^k
MPrime = MPrime + deltaPrime # next sub interval to take primes from
return [F, Pi]
def segSieveFac(n, delta): # optimal interval length once again I suppose
[F, Pi] = subSegSieveFac(n, delta, int(np.floor(np.sqrt(n + delta))))
for nPrime in range(n, n + delta + 1): # now properly collecting the primes and there power in F
if Pi[nPrime - n] != nPrime:
p0 = int(nPrime / Pi[nPrime - n])
F[nPrime - n].append([p0, 1])
return F
def newSegSieveFac(n, delta, K): # uses the diophantine thing to generate primes and factor instead
[FPrime, PiPrime] = subSegSieveFac(n - delta, 2 * delta, K * delta)
F = []
Pi = []
n0 = n - delta
for j in range(-delta, delta + 1):
F.append(FPrime[j + delta])
Pi.append(PiPrime[j + delta])
M = int(np.floor(K * delta)) + 1
while M <= np.sqrt(n + delta):
R = int(np.floor(M * np.sqrt(delta / (4 * n))))
m0 = M + R
a1 = n / (m0 * m0) % 1
a0 = n / m0 % 1
nu = 5 * delta / (4 * M)
aaq = diophApprox(a1, 2 * R)
c = int(np.floor(a0 * aaq[2] + 0.5))
k = int(np.floor(nu * aaq[2]))
for j in range(-k - 1, k + 2):
r0 = -aaq[1] * (c + j) % aaq[2]
kMin = int(np.ceil((M - m0 - r0) / aaq[2]))
kMax = int(np.floor((M + 2 * R - m0 - r0) / aaq[2]))
intersection = []
for i in range(kMin, kMax + 1):
intersection.append(m0 + r0 + aaq[2] * i)
for m in intersection:
nPrime = int(np.floor((n + delta)) / m) * m
if n - delta <= nPrime:
if nPrime <= n + delta: # very very similar down to here
if int(nPrime / Pi[nPrime - n0]) % m == 0: # now finding more prime divisors (I think)
if nPrime % (m * m) == 0:
Pi[nPrime - n0] = m * m * Pi[nPrime - n0]
F[nPrime - n0].append([m, 2])
else:
Pi[nPrime - n0] = m * Pi[nPrime - n0]
F[nPrime - n0].append([m, 1])
M = M + 2 * R + 1 # new interval once again
for nPrime in range(n0, n0 + 2 * delta + 1): # same meme again
if Pi[nPrime - n0] != nPrime:
p0 = int(nPrime / Pi[nPrime - n0])
F[nPrime - n0].append([p0, 1])
return F
def mobFun(facList):
for factors in facList:
if factors[1] > 1:
return 0
if facList[0][0] == 1:
return 1
return int(np.power(-1, len(facList) % 2))
def mobSumCheck(factorised, bound=0):
m = 1
max = 1
for facList in factorised:
m = m + mobFun(facList)
if m > max:
max = m
if (m > bound):
print('Holy fuck')
print(max)
return m
n1 = 5000000
d1 = n1 - 2
m1 = 13
K1 = 2.5
pr = cProfile.Profile()
pr.enable()
asdf = newSegSieve(n1, d1, K1)
pr.disable()
print(np.sum(asdf))
pr.print_stats()
# asdfasdf = segSieveFac(n1, d1)
# asdfasdfasdf = newSegSieveFac(n1, d1, K1)
primes = []
print()