/
test_connection.py
1509 lines (1157 loc) · 57.1 KB
/
test_connection.py
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from collections import namedtuple
from fixtures import * # noqa: F401,F403
from lightning import RpcError
from utils import DEVELOPER, only_one, wait_for, sync_blockheight, VALGRIND, EXPERIMENTAL_FEATURES
import os
import pytest
import time
import random
import shutil
import unittest
def test_connect(node_factory):
l1, l2 = node_factory.line_graph(2, fundchannel=False)
# These should be in openingd.
assert l1.rpc.getpeer(l2.info['id'])['connected']
assert l2.rpc.getpeer(l1.info['id'])['connected']
assert len(l1.rpc.getpeer(l2.info['id'])['channels']) == 0
assert len(l2.rpc.getpeer(l1.info['id'])['channels']) == 0
# Reconnect should be a noop
ret = l1.rpc.connect(l2.info['id'], 'localhost', port=l2.port)
assert ret['id'] == l2.info['id']
ret = l2.rpc.connect(l1.info['id'], host='localhost', port=l1.port)
assert ret['id'] == l1.info['id']
# Should still only have one peer!
assert len(l1.rpc.listpeers()) == 1
assert len(l2.rpc.listpeers()) == 1
# Should get reasonable error if unknown addr for peer.
with pytest.raises(RpcError, match=r'No address known'):
l1.rpc.connect('032cf15d1ad9c4a08d26eab1918f732d8ef8fdc6abb9640bf3db174372c491304e')
# Should get reasonable error if connection refuse.
with pytest.raises(RpcError, match=r'Connection establishment: Connection refused'):
l1.rpc.connect('032cf15d1ad9c4a08d26eab1918f732d8ef8fdc6abb9640bf3db174372c491304e', 'localhost', 1)
# Should get reasonable error if wrong key for peer.
with pytest.raises(RpcError, match=r'Cryptographic handshake: peer closed connection \(wrong key\?\)'):
l1.rpc.connect('032cf15d1ad9c4a08d26eab1918f732d8ef8fdc6abb9640bf3db174372c491304e', 'localhost', l2.port)
def test_connect_standard_addr(node_factory):
"""Test standard node@host:port address
"""
l1, l2, l3 = node_factory.get_nodes(3)
# node@host
ret = l1.rpc.connect("{}@{}".format(l2.info['id'], 'localhost'), port=l2.port)
assert ret['id'] == l2.info['id']
# node@host:port
ret = l1.rpc.connect("{}@localhost:{}".format(l3.info['id'], l3.port))
assert ret['id'] == l3.info['id']
# node@[ipv6]:port --- not supported by our CI
# ret = l1.rpc.connect("{}@[::1]:{}".format(l3.info['id'], l3.port))
# assert ret['id'] == l3.info['id']
def test_reconnect_channel_peers(node_factory, executor):
l1 = node_factory.get_node(may_reconnect=True)
l2 = node_factory.get_node(may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fund_channel(l2, 10**6)
l2.restart()
# Should reconnect.
wait_for(lambda: only_one(l1.rpc.listpeers(l2.info['id'])['peers'])['connected'])
wait_for(lambda: only_one(l2.rpc.listpeers(l1.info['id'])['peers'])['connected'])
# Connect command should succeed.
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
# Stop l2 and wait for l1 to notice.
l2.stop()
wait_for(lambda: not only_one(l1.rpc.listpeers(l2.info['id'])['peers'])['connected'])
# Now should fail.
with pytest.raises(RpcError, match=r'Connection refused'):
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
# Wait for exponential backoff to give us a 2 second window.
l1.daemon.wait_for_log('Will try reconnect in 2 seconds')
# It should now succeed when it restarts.
l2.start()
# Multiples should be fine!
fut1 = executor.submit(l1.rpc.connect, l2.info['id'], 'localhost', l2.port)
fut2 = executor.submit(l1.rpc.connect, l2.info['id'], 'localhost', l2.port)
fut3 = executor.submit(l1.rpc.connect, l2.info['id'], 'localhost', l2.port)
fut1.result(10)
fut2.result(10)
fut3.result(10)
def test_balance(node_factory):
l1, l2 = node_factory.line_graph(2, fundchannel=True)
p1 = only_one(l1.rpc.getpeer(peer_id=l2.info['id'], level='info')['channels'])
p2 = only_one(l2.rpc.getpeer(l1.info['id'], 'info')['channels'])
assert p1['msatoshi_to_us'] == 10**6 * 1000
assert p1['msatoshi_total'] == 10**6 * 1000
assert p2['msatoshi_to_us'] == 0
assert p2['msatoshi_total'] == 10**6 * 1000
def test_bad_opening(node_factory):
# l1 asks for a too-long locktime
l1 = node_factory.get_node(options={'watchtime-blocks': 100})
l2 = node_factory.get_node(options={'max-locktime-blocks': 99})
ret = l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
assert ret['id'] == l2.info['id']
l1.daemon.wait_for_log('openingd-.*: Handed peer, entering loop')
l2.daemon.wait_for_log('openingd-.*: Handed peer, entering loop')
l1.fundwallet(10**6 + 1000000)
with pytest.raises(RpcError):
l1.rpc.fundchannel(l2.info['id'], 10**6)
l2.daemon.wait_for_log('to_self_delay 100 larger than 99')
def test_second_channel(node_factory):
l1 = node_factory.get_node()
l2 = node_factory.get_node()
l3 = node_factory.get_node()
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.rpc.connect(l3.info['id'], 'localhost', l3.port)
l1.fund_channel(l2, 10**6)
l1.fund_channel(l3, 10**6)
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_disconnect(node_factory):
# These should all make us fail
disconnects = ['-WIRE_INIT',
'@WIRE_INIT',
'+WIRE_INIT']
l1 = node_factory.get_node(disconnect=disconnects)
l2 = node_factory.get_node()
with pytest.raises(RpcError):
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
with pytest.raises(RpcError):
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
with pytest.raises(RpcError):
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
# Should have 3 connect fails.
for d in disconnects:
l1.daemon.wait_for_log('Failed connected out for {}'
.format(l2.info['id']))
# Should still only have one peer!
assert len(l1.rpc.listpeers()) == 1
assert len(l2.rpc.listpeers()) == 1
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_disconnect_funder(node_factory):
# Now error on funder side duringchannel open.
disconnects = ['-WIRE_OPEN_CHANNEL',
'@WIRE_OPEN_CHANNEL',
'+WIRE_OPEN_CHANNEL',
'-WIRE_FUNDING_CREATED',
'@WIRE_FUNDING_CREATED']
l1 = node_factory.get_node(disconnect=disconnects)
l2 = node_factory.get_node()
l1.fundwallet(2000000)
for d in disconnects:
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
with pytest.raises(RpcError):
l1.rpc.fundchannel(l2.info['id'], 20000)
assert l1.rpc.getpeer(l2.info['id']) is None
# This one will succeed.
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.rpc.fundchannel(l2.info['id'], 20000)
# Should still only have one peer!
assert len(l1.rpc.listpeers()) == 1
assert len(l2.rpc.listpeers()) == 1
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_disconnect_fundee(node_factory):
# Now error on fundee side during channel open.
disconnects = ['-WIRE_ACCEPT_CHANNEL',
'@WIRE_ACCEPT_CHANNEL',
'+WIRE_ACCEPT_CHANNEL']
l1 = node_factory.get_node()
l2 = node_factory.get_node(disconnect=disconnects)
l1.fundwallet(2000000)
for d in disconnects:
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
with pytest.raises(RpcError):
l1.rpc.fundchannel(l2.info['id'], 20000)
assert l1.rpc.getpeer(l2.info['id']) is None
# This one will succeed.
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.rpc.fundchannel(l2.info['id'], 20000)
# Should still only have one peer!
assert len(l1.rpc.listpeers()) == 1
assert len(l2.rpc.listpeers()) == 1
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_disconnect_half_signed(node_factory):
# Now, these are the corner cases. Fundee sends funding_signed,
# but funder doesn't receive it.
disconnects = ['@WIRE_FUNDING_SIGNED']
l1 = node_factory.get_node()
l2 = node_factory.get_node(disconnect=disconnects)
l1.fundwallet(2000000)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
with pytest.raises(RpcError):
l1.rpc.fundchannel(l2.info['id'], 20000)
# Fundee remembers, funder doesn't.
assert l1.rpc.getpeer(l2.info['id']) is None
assert l2.rpc.getpeer(l1.info['id'])['id'] == l1.info['id']
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_reconnect_signed(node_factory):
# This will fail *after* both sides consider channel opening.
disconnects = ['+WIRE_FUNDING_SIGNED']
l1 = node_factory.get_node(may_reconnect=True)
l2 = node_factory.get_node(disconnect=disconnects,
may_reconnect=True)
l1.fundwallet(2000000)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.rpc.fundchannel(l2.info['id'], 20000)
# They haven't forgotten each other.
assert l1.rpc.getpeer(l2.info['id'])['id'] == l2.info['id']
assert l2.rpc.getpeer(l1.info['id'])['id'] == l1.info['id']
# Technically, this is async to fundchannel (and could reconnect first)
l1.daemon.wait_for_logs(['sendrawtx exit 0',
'Peer has reconnected, state CHANNELD_AWAITING_LOCKIN'])
l1.bitcoin.generate_block(6)
l1.daemon.wait_for_log(' to CHANNELD_NORMAL')
l2.daemon.wait_for_log(' to CHANNELD_NORMAL')
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_reconnect_openingd(node_factory):
# Openingd thinks we're still opening; funder reconnects..
disconnects = ['0WIRE_ACCEPT_CHANNEL']
l1 = node_factory.get_node(may_reconnect=True)
l2 = node_factory.get_node(disconnect=disconnects,
may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fundwallet(2000000)
# l2 closes on l1, l1 forgets.
with pytest.raises(RpcError):
l1.rpc.fundchannel(l2.info['id'], 20000)
assert l1.rpc.getpeer(l2.info['id']) is None
# Reconnect.
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
# We should get a message about reconnecting.
l2.daemon.wait_for_log('Killing openingd: Reconnected')
l2.daemon.wait_for_log('lightning_openingd.*Handed peer, entering loop')
# Should work fine.
l1.rpc.fundchannel(l2.info['id'], 20000)
l1.daemon.wait_for_log('sendrawtx exit 0')
# Just to be sure, second openingd hand over to channeld.
l2.daemon.wait_for_log('lightning_openingd.*UPDATE WIRE_OPENING_FUNDEE')
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_reconnect_gossiping(node_factory):
# connectd thinks we're still gossiping; peer reconnects.
disconnects = ['0WIRE_PING']
l1 = node_factory.get_node(may_reconnect=True)
l2 = node_factory.get_node(disconnect=disconnects,
may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l2.rpc.ping(l1.info['id'], 1, 65532)
wait_for(lambda: l1.rpc.listpeers(l2.info['id'])['peers'] == [])
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l2.daemon.wait_for_log('processing now old peer gone')
def test_connect_stresstest(node_factory, executor):
# This test is unreliable, but it's better than nothing.
l1 = node_factory.get_node(may_reconnect=True)
l2 = node_factory.get_node(may_reconnect=True)
l3 = node_factory.get_node(may_reconnect=True)
# Hack l3 into a clone of l2, to stress reconnect code.
l3.stop()
shutil.copyfile(os.path.join(l2.daemon.lightning_dir, 'hsm_secret'),
os.path.join(l3.daemon.lightning_dir, 'hsm_secret'))
l3.start()
l3.info = l3.rpc.getinfo()
assert l3.info['id'] == l2.info['id']
# We fire off random connect/disconnect commands.
actions = [
(l2.rpc.connect, l1.info['id'], 'localhost', l1.port),
(l3.rpc.connect, l1.info['id'], 'localhost', l3.port),
(l1.rpc.connect, l2.info['id'], 'localhost', l2.port),
(l1.rpc.connect, l3.info['id'], 'localhost', l3.port),
(l1.rpc.disconnect, l2.info['id'])
]
args = [random.choice(actions) for _ in range(1000)]
# We get them all to connect to each other.
futs = []
for a in args:
futs.append(executor.submit(*a))
# We don't actually care if they fail, since some will.
successes = 0
failures = 0
for f in futs:
if f.exception():
failures += 1
else:
f.result()
successes += 1
assert successes > failures
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_reconnect_normal(node_factory):
# Should reconnect fine even if locked message gets lost.
disconnects = ['-WIRE_FUNDING_LOCKED',
'@WIRE_FUNDING_LOCKED',
'+WIRE_FUNDING_LOCKED']
l1 = node_factory.get_node(disconnect=disconnects,
may_reconnect=True)
l2 = node_factory.get_node(may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fund_channel(l2, 10**6)
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_reconnect_sender_add1(node_factory):
# Fail after add is OK, will cause payment failure though.
disconnects = ['-WIRE_UPDATE_ADD_HTLC-nocommit',
'+WIRE_UPDATE_ADD_HTLC-nocommit',
'@WIRE_UPDATE_ADD_HTLC-nocommit']
# Feerates identical so we don't get gratuitous commit to update them
l1 = node_factory.get_node(disconnect=disconnects,
may_reconnect=True,
feerates=(7500, 7500, 7500))
l2 = node_factory.get_node(may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fund_channel(l2, 10**6)
amt = 200000000
rhash = l2.rpc.invoice(amt, 'test_reconnect_sender_add1', 'desc')['payment_hash']
assert only_one(l2.rpc.listinvoices('test_reconnect_sender_add1')['invoices'])['status'] == 'unpaid'
route = [{'msatoshi': amt, 'id': l2.info['id'], 'delay': 5, 'channel': '1:1:1'}]
for i in range(0, len(disconnects)):
l1.rpc.sendpay(route, rhash)
with pytest.raises(RpcError):
l1.rpc.waitsendpay(rhash)
# Wait for reconnection.
l1.daemon.wait_for_log('Already have funding locked in')
# This will send commit, so will reconnect as required.
l1.rpc.sendpay(route, rhash)
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_reconnect_sender_add(node_factory):
disconnects = ['-WIRE_COMMITMENT_SIGNED',
'@WIRE_COMMITMENT_SIGNED',
'+WIRE_COMMITMENT_SIGNED',
'-WIRE_REVOKE_AND_ACK',
'@WIRE_REVOKE_AND_ACK',
'+WIRE_REVOKE_AND_ACK']
# Feerates identical so we don't get gratuitous commit to update them
l1 = node_factory.get_node(disconnect=disconnects,
may_reconnect=True,
feerates=(7500, 7500, 7500))
l2 = node_factory.get_node(may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fund_channel(l2, 10**6)
amt = 200000000
rhash = l2.rpc.invoice(amt, 'testpayment', 'desc')['payment_hash']
assert only_one(l2.rpc.listinvoices('testpayment')['invoices'])['status'] == 'unpaid'
route = [{'msatoshi': amt, 'id': l2.info['id'], 'delay': 5, 'channel': '1:1:1'}]
# This will send commit, so will reconnect as required.
l1.rpc.sendpay(route, rhash)
# Should have printed this for every reconnect.
for i in range(0, len(disconnects)):
l1.daemon.wait_for_log('Already have funding locked in')
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_reconnect_receiver_add(node_factory):
disconnects = ['-WIRE_COMMITMENT_SIGNED',
'@WIRE_COMMITMENT_SIGNED',
'+WIRE_COMMITMENT_SIGNED',
'-WIRE_REVOKE_AND_ACK',
'@WIRE_REVOKE_AND_ACK',
'+WIRE_REVOKE_AND_ACK']
# Feerates identical so we don't get gratuitous commit to update them
l1 = node_factory.get_node(may_reconnect=True, feerates=(7500, 7500, 7500))
l2 = node_factory.get_node(disconnect=disconnects,
may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fund_channel(l2, 10**6)
amt = 200000000
rhash = l2.rpc.invoice(amt, 'testpayment2', 'desc')['payment_hash']
assert only_one(l2.rpc.listinvoices('testpayment2')['invoices'])['status'] == 'unpaid'
route = [{'msatoshi': amt, 'id': l2.info['id'], 'delay': 5, 'channel': '1:1:1'}]
l1.rpc.sendpay(route, rhash)
for i in range(len(disconnects)):
l1.daemon.wait_for_log('Already have funding locked in')
assert only_one(l2.rpc.listinvoices('testpayment2')['invoices'])['status'] == 'paid'
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_reconnect_receiver_fulfill(node_factory):
# Ordering matters: after +WIRE_UPDATE_FULFILL_HTLC, channeld
# will continue and try to send WIRE_COMMITMENT_SIGNED: if
# that's the next failure, it will do two in one run.
disconnects = ['@WIRE_UPDATE_FULFILL_HTLC',
'+WIRE_UPDATE_FULFILL_HTLC',
'-WIRE_UPDATE_FULFILL_HTLC',
'-WIRE_COMMITMENT_SIGNED',
'@WIRE_COMMITMENT_SIGNED',
'+WIRE_COMMITMENT_SIGNED',
'-WIRE_REVOKE_AND_ACK',
'@WIRE_REVOKE_AND_ACK',
'+WIRE_REVOKE_AND_ACK']
l1 = node_factory.get_node(may_reconnect=True)
l2 = node_factory.get_node(disconnect=disconnects,
may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fund_channel(l2, 10**6)
amt = 200000000
rhash = l2.rpc.invoice(amt, 'testpayment2', 'desc')['payment_hash']
assert only_one(l2.rpc.listinvoices('testpayment2')['invoices'])['status'] == 'unpaid'
route = [{'msatoshi': amt, 'id': l2.info['id'], 'delay': 5, 'channel': '1:1:1'}]
l1.rpc.sendpay(route, rhash)
for i in range(len(disconnects)):
l1.daemon.wait_for_log('Already have funding locked in')
assert only_one(l2.rpc.listinvoices('testpayment2')['invoices'])['status'] == 'paid'
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_shutdown_reconnect(node_factory):
disconnects = ['-WIRE_SHUTDOWN',
'@WIRE_SHUTDOWN',
'+WIRE_SHUTDOWN']
l1 = node_factory.get_node(disconnect=disconnects,
may_reconnect=True)
l2 = node_factory.get_node(may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
chan = l1.fund_channel(l2, 10**6)
l1.pay(l2, 200000000)
assert l1.bitcoin.rpc.getmempoolinfo()['size'] == 0
# This should return with an error, then close.
with pytest.raises(RpcError, match=r'Channel close negotiation not finished'):
l1.rpc.close(chan, False, 0)
l1.daemon.wait_for_log(' to CHANNELD_SHUTTING_DOWN')
l2.daemon.wait_for_log(' to CHANNELD_SHUTTING_DOWN')
l1.daemon.wait_for_log(' to CLOSINGD_SIGEXCHANGE')
l2.daemon.wait_for_log(' to CLOSINGD_SIGEXCHANGE')
# And should put closing into mempool (happens async, so
# CLOSINGD_COMPLETE may come first).
l1.daemon.wait_for_logs(['sendrawtx exit 0', ' to CLOSINGD_COMPLETE'])
l2.daemon.wait_for_logs(['sendrawtx exit 0', ' to CLOSINGD_COMPLETE'])
assert l1.bitcoin.rpc.getmempoolinfo()['size'] == 1
def test_shutdown_awaiting_lockin(node_factory, bitcoind):
l1 = node_factory.get_node()
l2 = node_factory.get_node(options={'funding-confirms': 3})
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fundwallet(10**6 + 1000000)
chanid = l1.rpc.fundchannel(l2.info['id'], 10**6)['channel_id']
# Technically, this is async to fundchannel.
l1.daemon.wait_for_log('sendrawtx exit 0')
bitcoind.generate_block(1)
# This should return with an error, then close.
with pytest.raises(RpcError, match=r'Channel close negotiation not finished'):
l1.rpc.close(chanid, False, 0)
l1.daemon.wait_for_log('CHANNELD_AWAITING_LOCKIN to CHANNELD_SHUTTING_DOWN')
l2.daemon.wait_for_log('CHANNELD_AWAITING_LOCKIN to CHANNELD_SHUTTING_DOWN')
l1.daemon.wait_for_log('CHANNELD_SHUTTING_DOWN to CLOSINGD_SIGEXCHANGE')
l2.daemon.wait_for_log('CHANNELD_SHUTTING_DOWN to CLOSINGD_SIGEXCHANGE')
# And should put closing into mempool (happens async, so
# CLOSINGD_COMPLETE may come first).
l1.daemon.wait_for_logs(['sendrawtx exit 0', ' to CLOSINGD_COMPLETE'])
l2.daemon.wait_for_logs(['sendrawtx exit 0', ' to CLOSINGD_COMPLETE'])
assert bitcoind.rpc.getmempoolinfo()['size'] == 1
bitcoind.generate_block(1)
l1.daemon.wait_for_log(' to ONCHAIN')
l2.daemon.wait_for_log(' to ONCHAIN')
bitcoind.generate_block(100)
wait_for(lambda: l1.rpc.listpeers()['peers'] == [])
wait_for(lambda: l2.rpc.listpeers()['peers'] == [])
def test_funding_change(node_factory, bitcoind):
"""Add some funds, fund a channel, and make sure we remember the change
"""
l1, l2 = node_factory.line_graph(2, fundchannel=False)
l1.fundwallet(10000000)
bitcoind.generate_block(1)
sync_blockheight(bitcoind, [l1])
outputs = l1.db_query('SELECT value FROM outputs WHERE status=0;')
assert only_one(outputs)['value'] == 10000000
l1.rpc.fundchannel(l2.info['id'], 1000000)
outputs = {r['status']: r['value'] for r in l1.db_query(
'SELECT status, SUM(value) AS value FROM outputs GROUP BY status;')}
# The 10m out is spent and we have a change output of 9m-fee
assert outputs[0] > 8990000
assert outputs[2] == 10000000
def test_funding_all(node_factory, bitcoind):
"""Add some funds, fund a channel using all funds, make sure no funds remain
"""
l1, l2 = node_factory.line_graph(2, fundchannel=False)
l1.fundwallet(0.1 * 10**8)
bitcoind.generate_block(1)
sync_blockheight(bitcoind, [l1])
outputs = l1.db_query('SELECT value FROM outputs WHERE status=0;')
assert only_one(outputs)['value'] == 10000000
l1.rpc.fundchannel(l2.info['id'], "all")
outputs = l1.db_query('SELECT value FROM outputs WHERE status=0;')
assert len(outputs) == 0
def test_funding_all_too_much(node_factory):
"""Add more than max possible funds, fund a channel using all funds we can.
"""
l1, l2 = node_factory.line_graph(2, fundchannel=False)
l1.fundwallet(2**24 + 10000)
l1.rpc.fundchannel(l2.info['id'], "all")
assert only_one(l1.rpc.listfunds()['outputs'])['status'] == 'unconfirmed'
assert only_one(l1.rpc.listfunds()['channels'])['channel_total_sat'] == 2**24 - 1
def test_funding_fail(node_factory, bitcoind):
"""Add some funds, fund a channel without enough funds"""
# Previous runs with same bitcoind can leave funds!
max_locktime = 5 * 6 * 24
l1 = node_factory.get_node(random_hsm=True, options={'max-locktime-blocks': max_locktime})
l2 = node_factory.get_node(options={'watchtime-blocks': max_locktime + 1})
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
funds = 1000000
addr = l1.rpc.newaddr()['address']
l1.bitcoin.rpc.sendtoaddress(addr, funds / 10**8)
bitcoind.generate_block(1)
# Wait for it to arrive.
wait_for(lambda: len(l1.rpc.listfunds()['outputs']) > 0)
# Fail because l1 dislikes l2's huge locktime.
with pytest.raises(RpcError, match=r'to_self_delay \d+ larger than \d+'):
l1.rpc.fundchannel(l2.info['id'], int(funds / 10))
assert only_one(l1.rpc.listpeers()['peers'])['connected']
assert only_one(l2.rpc.listpeers()['peers'])['connected']
# Restart l2 without ridiculous locktime.
del l2.daemon.opts['watchtime-blocks']
l2.restart()
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
# We don't have enough left to cover fees if we try to spend it all.
with pytest.raises(RpcError, match=r'Cannot afford transaction'):
l1.rpc.fundchannel(l2.info['id'], funds)
# Should still be connected.
assert only_one(l1.rpc.listpeers()['peers'])['connected']
l2.daemon.wait_for_log('lightning_openingd-.*: Handed peer, entering loop')
assert only_one(l2.rpc.listpeers()['peers'])['connected']
# This works.
l1.rpc.fundchannel(l2.info['id'], int(funds / 10))
def test_funding_toolarge(node_factory, bitcoind):
"""Try to create a giant channel"""
l1 = node_factory.get_node()
l2 = node_factory.get_node()
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
# Send funds.
amount = 2**24
bitcoind.rpc.sendtoaddress(l1.rpc.newaddr()['address'], amount / 10**8 + 0.01)
bitcoind.generate_block(1)
# Wait for it to arrive.
wait_for(lambda: len(l1.rpc.listfunds()['outputs']) > 0)
# Fail to open (too large)
with pytest.raises(RpcError, match=r'Amount exceeded 16777215'):
l1.rpc.fundchannel(l2.info['id'], amount)
# This should work.
amount = amount - 1
l1.rpc.fundchannel(l2.info['id'], amount)
def test_lockin_between_restart(node_factory, bitcoind):
l1 = node_factory.get_node(may_reconnect=True)
l2 = node_factory.get_node(options={'funding-confirms': 3},
may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fundwallet(10**6 + 1000000)
l1.rpc.fundchannel(l2.info['id'], 10**6)['tx']
# l1 goes down.
l1.stop()
# Now 120 blocks go by...
bitcoind.generate_block(120)
# Restart
l1.start()
# All should be good.
l1.daemon.wait_for_log(' to CHANNELD_NORMAL')
l2.daemon.wait_for_log(' to CHANNELD_NORMAL')
def test_funding_while_offline(node_factory, bitcoind):
l1 = node_factory.get_node()
addr = l1.rpc.newaddr()['address']
sync_blockheight(bitcoind, [l1])
# l1 goes down.
l1.stop()
# We send funds
bitcoind.rpc.sendtoaddress(addr, (10**6 + 1000000) / 10**8)
# Now 120 blocks go by...
bitcoind.generate_block(120)
# Restart
l1.start()
sync_blockheight(bitcoind, [l1])
assert len(l1.rpc.listfunds()['outputs']) == 1
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_channel_persistence(node_factory, bitcoind, executor):
# Start two nodes and open a channel (to remember). l2 will
# mysteriously die while committing the first HTLC so we can
# check that HTLCs reloaded from the DB work.
# Feerates identical so we don't get gratuitous commit to update them
l1 = node_factory.get_node(may_reconnect=True, feerates=(7500, 7500, 7500))
l2 = node_factory.get_node(disconnect=['=WIRE_COMMITMENT_SIGNED-nocommit'],
may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
# Neither node should have a channel open, they are just connected
for n in (l1, l2):
assert(n.db_query('SELECT COUNT(id) as count FROM channels;')[0]['count'] == 0)
l1.fund_channel(l2, 100000)
peers = l1.rpc.listpeers()['peers']
assert(only_one(peers[0]['channels'])['state'] == 'CHANNELD_NORMAL')
# Both nodes should now have exactly one channel in the database
for n in (l1, l2):
assert(n.db_query('SELECT COUNT(id) as count FROM channels;')[0]['count'] == 1)
# Fire off a sendpay request, it'll get interrupted by a restart
executor.submit(l1.pay, l2, 10000)
# Wait for it to be committed to, i.e., stored in the DB
l1.daemon.wait_for_log('peer_in WIRE_COMMITMENT_SIGNED')
# Stop l2, l1 will reattempt to connect
print("Killing l2 in mid HTLC")
l2.daemon.kill()
# Clear the disconnect and timer stop so we can proceed normally
del l2.daemon.opts['dev-disconnect']
# Wait for l1 to notice
wait_for(lambda: 'connected' not in only_one(l1.rpc.listpeers()['peers'][0]['channels']))
# Now restart l2 and it should reload peers/channels from the DB
l2.start()
wait_for(lambda: len(l2.rpc.listpeers()['peers']) == 1)
# Wait for the restored HTLC to finish
wait_for(lambda: only_one(l1.rpc.listpeers()['peers'][0]['channels'])['msatoshi_to_us'] == 99990000)
wait_for(lambda: len([p for p in l1.rpc.listpeers()['peers'] if p['connected']]))
wait_for(lambda: len([p for p in l2.rpc.listpeers()['peers'] if p['connected']]))
# Now make sure this is really functional by sending a payment
l1.pay(l2, 10000)
# L1 doesn't actually update msatoshi_to_us until it receives
# revoke_and_ack from L2, which can take a little bit.
wait_for(lambda: only_one(l1.rpc.listpeers()['peers'][0]['channels'])['msatoshi_to_us'] == 99980000)
assert only_one(l2.rpc.listpeers()['peers'][0]['channels'])['msatoshi_to_us'] == 20000
# Finally restart l1, and make sure it remembers
l1.restart()
assert only_one(l1.rpc.listpeers()['peers'][0]['channels'])['msatoshi_to_us'] == 99980000
# Now make sure l1 is watching for unilateral closes
l2.rpc.dev_fail(l1.info['id'])
l2.daemon.wait_for_log('Failing due to dev-fail command')
l2.wait_for_channel_onchain(l1.info['id'])
bitcoind.generate_block(1)
# L1 must notice.
l1.daemon.wait_for_log(' to ONCHAIN')
def test_private_channel(node_factory):
l1, l2 = node_factory.line_graph(2, announce_channels=False, wait_for_announce=False)
l3, l4 = node_factory.line_graph(2, announce_channels=True, wait_for_announce=True)
assert l1.daemon.is_in_log('Will open private channel with node {}'.format(l2.info['id']))
assert not l2.daemon.is_in_log('Will open private channel with node {}'.format(l1.info['id']))
assert not l3.daemon.is_in_log('Will open private channel with node {}'.format(l4.info['id']))
l3.daemon.wait_for_log('Received node_announcement for node {}'.format(l4.info['id']))
l4.daemon.wait_for_log('Received node_announcement for node {}'.format(l3.info['id']))
assert not l1.daemon.is_in_log('Received node_announcement for node {}'.format(l2.info['id']))
assert not l2.daemon.is_in_log('Received node_announcement for node {}'.format(l1.info['id']))
# test for 'private' flag in rpc output
assert only_one(only_one(l1.rpc.listpeers(l2.info['id'])['peers'])['channels'])['private']
# check non-private channel
assert not only_one(only_one(l4.rpc.listpeers(l3.info['id'])['peers'])['channels'])['private']
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1 for --dev-broadcast-interval")
def test_channel_reenable(node_factory):
l1, l2 = node_factory.line_graph(2, opts={'may_reconnect': True}, fundchannel=True, wait_for_announce=True)
l1.daemon.wait_for_log('Received node_announcement for node {}'.format(l2.info['id']))
l2.daemon.wait_for_log('Received node_announcement for node {}'.format(l1.info['id']))
# Both directions should be active before the restart
wait_for(lambda: [c['active'] for c in l1.rpc.listchannels()['channels']] == [True, True])
# Restart l2, will cause l1 to reconnect
l2.stop()
wait_for(lambda: [c['active'] for c in l1.rpc.listchannels()['channels']] == [False, False])
l2.start()
# Updates may be suppressed if redundant; just test results.
wait_for(lambda: [c['active'] for c in l1.rpc.listchannels()['channels']] == [True, True])
wait_for(lambda: [c['active'] for c in l2.rpc.listchannels()['channels']] == [True, True])
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_update_fee(node_factory, bitcoind):
l1, l2 = node_factory.line_graph(2, fundchannel=True)
chanid = l1.get_channel_scid(l2)
# Make l1 send out feechange.
l1.set_feerates((14000, 7500, 3750))
l2.daemon.wait_for_log('peer updated fee to 14000')
# Now make sure an HTLC works.
# (First wait for route propagation.)
l1.wait_channel_active(chanid)
sync_blockheight(bitcoind, [l1, l2])
# Make payments.
l1.pay(l2, 200000000)
l2.pay(l1, 100000000)
# Now shutdown cleanly.
with pytest.raises(RpcError, match=r'Channel close negotiation not finished'):
l1.rpc.close(chanid, False, 0)
l1.daemon.wait_for_log(' to CLOSINGD_COMPLETE')
l2.daemon.wait_for_log(' to CLOSINGD_COMPLETE')
# And should put closing into mempool.
l1.wait_for_channel_onchain(l2.info['id'])
l2.wait_for_channel_onchain(l1.info['id'])
bitcoind.generate_block(1)
l1.daemon.wait_for_log(' to ONCHAIN')
l2.daemon.wait_for_log(' to ONCHAIN')
bitcoind.generate_block(99)
l1.daemon.wait_for_log('onchaind complete, forgetting peer')
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_fee_limits(node_factory):
# FIXME: Test case where opening denied.
l1, l2 = node_factory.line_graph(2, opts={'dev-max-fee-multiplier': 5, 'may_reconnect': True}, fundchannel=True)
# L1 asks for stupid low fee (will actually hit the floor of 253)
l1.stop()
l1.set_feerates((15, 15, 15), False)
l1.start()
l1.daemon.wait_for_log('Peer permanent failure in CHANNELD_NORMAL: lightning_channeld: received ERROR channel .*: update_fee 253 outside range 1875-75000')
# Make sure the resolution of this one doesn't interfere with the next!
# Note: may succeed, may fail with insufficient fee, depending on how
# bitcoind feels!
l1.daemon.wait_for_log('sendrawtx exit')
# Restore to normal.
l1.stop()
l1.set_feerates((15000, 7500, 3750), False)
l1.start()
# Try with node which sets --ignore-fee-limits
l3 = node_factory.get_node(options={'ignore-fee-limits': 'true'}, may_reconnect=True)
l1.rpc.connect(l3.info['id'], 'localhost', l3.port)
chan = l1.fund_channel(l3, 10**6)
# Try stupid high fees
l1.stop()
l1.set_feerates((15000 * 10, 7500, 3750), False)
l1.start()
l3.daemon.wait_for_log('peer_in WIRE_UPDATE_FEE')
l3.daemon.wait_for_log('peer_in WIRE_COMMITMENT_SIGNED')
# We need to wait until both have committed and revoked the
# old state, otherwise we'll still try to commit with the old
# 15sat/byte fee
l1.daemon.wait_for_log('peer_out WIRE_REVOKE_AND_ACK')
# This should wait for close to complete
l1.rpc.close(chan)
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_update_fee_reconnect(node_factory, bitcoind):
# Disconnect after first commitsig.
disconnects = ['+WIRE_COMMITMENT_SIGNED']
# Feerates identical so we don't get gratuitous commit to update them
l1 = node_factory.get_node(disconnect=disconnects, may_reconnect=True,
feerates=(15000, 15000, 3750))
# We match l2's later feerate, so we agree on same closing tx for simplicity.
l2 = node_factory.get_node(may_reconnect=True,
feerates=(14000, 14000, 3750))
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
chan = l1.fund_channel(l2, 10**6)
# Make l1 send out feechange; triggers disconnect/reconnect.
# (Note: < 10% change, so no smoothing here!)
l1.set_feerates((14000, 14000, 3750))
l1.daemon.wait_for_log('Setting REMOTE feerate to 14000')
l2.daemon.wait_for_log('Setting LOCAL feerate to 14000')
l1.daemon.wait_for_log(r'dev_disconnect: \+WIRE_COMMITMENT_SIGNED')
# Wait for reconnect....
l1.daemon.wait_for_log('Applying feerate 14000 to LOCAL')
l1.pay(l2, 200000000)
l2.pay(l1, 100000000)
# They should both have gotten commits with correct feerate.
assert l1.daemon.is_in_log('got commitsig [0-9]*: feerate 14000')
assert l2.daemon.is_in_log('got commitsig [0-9]*: feerate 14000')
# Now shutdown cleanly.
l1.rpc.close(chan)
# And should put closing into mempool.
l1.wait_for_channel_onchain(l2.info['id'])
l2.wait_for_channel_onchain(l1.info['id'])
bitcoind.generate_block(1)
l1.daemon.wait_for_log(' to ONCHAIN')
l2.daemon.wait_for_log(' to ONCHAIN')
bitcoind.generate_block(99)
l1.daemon.wait_for_log('onchaind complete, forgetting peer')
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
@unittest.skipIf(not DEVELOPER, "Too slow without --dev-bitcoind-poll")
def test_multiple_channels(node_factory):
l1 = node_factory.get_node()
l2 = node_factory.get_node()
for i in range(3):
# FIXME: we shouldn't disconnect on close?
ret = l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
assert ret['id'] == l2.info['id']
l1.daemon.wait_for_log('openingd-.*: Handed peer, entering loop')
l2.daemon.wait_for_log('openingd-.*: Handed peer, entering loop')
chan = l1.fund_channel(l2, 10**6)
l1.rpc.close(chan)
channels = only_one(l1.rpc.listpeers()['peers'])['channels']
assert len(channels) == 3
# Most in state ONCHAIN, last is CLOSINGD_COMPLETE
for i in range(len(channels) - 1):
assert channels[i]['state'] == 'ONCHAIN'
assert channels[-1]['state'] == 'CLOSINGD_COMPLETE'
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_forget_channel(node_factory):
l1 = node_factory.get_node()
l2 = node_factory.get_node()
l1.fundwallet(10**6)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.rpc.fundchannel(l2.info['id'], 10**5)
assert len(l1.rpc.listpeers()['peers']) == 1
# This should fail, the funding tx is in the mempool and may confirm
with pytest.raises(RpcError, match=r'Cowardly refusing to forget channel'):
l1.rpc.dev_forget_channel(l2.info['id'])
assert len(l1.rpc.listpeers()['peers']) == 1