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Bilibili p31-33 my note videos p30-31
Bilibili p31-33
my note videos p30-31
How probability come down to counting
6 coin flipping, if the outcome is 3 heads 3 tails, win 20 dollars; otherwise, lose 10 dollars; will you bet? outcome Assumptions fair coin = p = 0.5 = 50% independence: first H or T, no effect on second H or T so, all outcomes are equally likely two questions how many possible outcomes are there how many involve 3 heads and 3 tails solution to question 1 steps = 6 coins flipping options = 2 head or tail independent, repetition allowed = $2^6$ solution to question 2 steps = take 3 coins to be heads = k options = 6 positions or flips = n inside 3-heads group, the order no matter = collection count $ = (^n_k)= (^6_3)$ favorable outcome 3 heads and 3 tails probability formula p = $(^6_3)/2^6$
6 coin flipping, if the outcome is 3 heads 3 tails, win 20 dollars; otherwise, lose 10 dollars; will you bet?
outcome
Assumptions
two questions
solution to question 1
solution to question 2
favorable outcome
probability formula
8 coin flipping, what is the probability of getting 4 heads? Experiment steps = 8 options = 2 constraint = 4 heads out of 8 flips total 8 steps, each step has 2 options, repetition allowed = $2^8$ interest 4 heads(4 tails), not 1 head, or 2, 3, 5, 6, 7, 8 heads 8 slots, choose 4 slots as a group, uniqueness defined by its location distinction order inside the 4 slots does not matter $(^8_4)$ probability = $(^8_4)/2^8$ What is the probability of getting 4, 5, or 6 heads out of 10 coin flipping? 4 heads prob = $(^{10}_4)/2^{10}$ 5 heads prob = $(^{10}_5)/2^{10}$ 6 heads prob = $(^{10}_6)/2^{10}$ add them together
Experiment
total
interest
probability = $(^8_4)/2^8$
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Flipping coins
video links
key question
Problem
Practice
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