Error with the modulo operator

[Ecoral360]

If you take the modulo of a variable while in a for loop (the variable must be the one used by the for loop (i in the example)), it yields a tuple where the first element is the floor division and the second element is the actual modulo
Ex:

for i in range(100)
    print(i % 2) # yields (i // 2, i % 2)

[ALavallee]

Thank you so much for findings these bugs ! :D

I'll take a look at this right now !

[Ecoral360]

I'm trying to test the speed of the compiler against Cython by comparing their speed for finding prime numbers (that's how I ran into those bugs :D)

[ALavallee]

Love that =) ! <3
Keep up the good work !

[ALavallee]

If you're doing benchmark I just want to note that the for each loop with integers optimization is not in yet. You're going to see a HUGE difference when it will be.

[Ecoral360]

Perfect! I'll keep that in mind!

[ALavallee]

Done in 4e83c84:

[ALavallee]

Should be good. Because of wrong ID it was actually calling the divmod binary func instead of the remainder one.

Thank you again ! :D