Alice plays the following game, loosely based on the card game "21".
Alice starts with 0 points, and draws numbers while she has less than K points. During each draw, she gains an integer number of points randomly from the range [1, W], where W is an integer. Each draw is independent and the outcomes have equal probabilities.
Alice stops drawing numbers when she gets K or more points. What is the probability that she has N or less points?
Example 1:
Input: N = 10, K = 1, W = 10
Output: 1.00000
Explanation: Alice gets a single card, then stops.
Example 2:
Input: N = 6, K = 1, W = 10
Output: 0.60000
Explanation: Alice gets a single card, then stops.
In 6 out of W = 10 possibilities, she is at or below N = 6 points.
Example 3:
Input: N = 21, K = 17, W = 10
Output: 0.73278
Note:
- 0 <= K <= N <= 10000
- 1 <= W <= 10000
- Answers will be accepted as correct if they are within 10^-5 of the correct answer.
- The judging time limit has been reduced for this question.
dp[i]=sum(dp[j] for j in range(i-W, i))
brute force, O(WK), tle (96/146):
class Solution(object):
def new21Game(self, N, K, W):
"""
:type N: int
:type K: int
:type W: int
:rtype: float
"""
dp=[0.0]*(K+W+1)
dp[0]=1.0
for i in range(K):
for j in range(i+1, i+W+1):
dp[j]+=dp[i]/W
return sum(dp[i] for i in range(K, N+1))
maintain a sliding window, pay attention to corner cases, O(K+W):
class Solution(object):
def new21Game(self, N, K, W):
"""
:type N: int
:type K: int
:type W: int
:rtype: float
"""
dp=[0.0]*(K+W+1)
dp[0]=1.0
s=1.0
for i in range(1, len(dp)):
dp[i]=s/W
if i>=W:
s-=dp[i-W]
if i<K:
s+=dp[i]
return min(1.0, sum(dp[i] for i in range(K, N+1)))