Numbers can be regarded as product of its factors. For example,
8 = 2 x 2 x 2;
= 2 x 4.
Write a function that takes an integer n and return all possible combinations of its factors.
Note:
- You may assume that n is always positive.
- Factors should be greater than 1 and less than n.
Examples:
input: 1
output:
[]
input: 37
output:
[]
input: 12
output:
[
[2, 6],
[2, 2, 3],
[3, 4]
]
input: 32
output:
[
[2, 16],
[2, 2, 8],
[2, 2, 2, 4],
[2, 2, 2, 2, 2],
[2, 4, 4],
[4, 8]
]
idx, prevent (2,3,2...):
class Solution(object):
def getFactors(self, n):
"""
:type n: int
:rtype: List[List[int]]
"""
res=[]
self.helper(2, n, [], res)
return res
def helper(self, idx, n, path, res):
for i in range(idx, int(n**0.5+1)):
if n%i==0:
res.append(path+[i, n/i])
self.helper(i, n/i, path+[i], res)