dev/democards/problems/problems/121.best-time-to-buy-and-sell-stock.ipynb

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   "cell_type": "markdown",
   "source": [
    "Say you have an array for which the _i_ th element is the price of a given\n",
    "stock on day _i_.\n",
    "\n",
    "If you were only permitted to complete at most one transaction (i.e., buy one\n",
    "and sell one share of the stock), design an algorithm to find the maximum\n",
    "profit.\n",
    "\n",
    "Note that you cannot sell a stock before you buy one.\n",
    "\n",
    "**Example 1:**\n",
    "\n",
    "\n",
    "\n",
    "    Input: [7,1,5,3,6,4]\n",
    "    Output: 5\n",
    "    Explanation: Buy on day 2 (price = 1) and sell on day 5 (price = 6), profit = 6-1 = 5.\n",
    "                 Not 7-1 = 6, as selling price needs to be larger than buying price.\n",
    "\n",
    "\n",
    "**Example 2:**\n",
    "\n",
    "\n",
    "\n",
    "    Input: [7,6,4,3,1]\n",
    "    Output: 0\n",
    "    Explanation: In this case, no transaction is done, i.e. max profit = 0."
   ],
   "metadata": {}
  },
  {
   "outputs": [
    {
     "output_type": "execute_result",
     "data": {
      "text/plain": "max_profit_121 (generic function with 1 method)"
     },
     "metadata": {},
     "execution_count": 1
    }
   ],
   "cell_type": "code",
   "source": [
    "# @lc code=start\n",
    "using LeetCode\n",
    "\n",
    "function max_profit_121(prices::Vector{Int})::Int\n",
    "    min_cost, profit = prices[1], 0\n",
    "    for price in @view prices[2:end]\n",
    "        profit = max(profit, price - min_cost)\n",
    "        min_cost = min(min_cost, price)\n",
    "    end\n",
    "    return profit\n",
    "end\n",
    "\n",
    "# @lc code=end"
   ],
   "metadata": {},
   "execution_count": 1
  },
  {
   "cell_type": "markdown",
   "source": [
    "---\n",
    "\n",
    "*This notebook was generated using [Literate.jl](https://github.com/fredrikekre/Literate.jl).*"
   ],
   "metadata": {}
  }
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