Wrong python (from wrong anaconda environment) when building PyCall with ENV["PYTHON"]

[h-spiess]

Hey,

I tried to use PyCall with the python i have installed in one of my anaconda environments. Unfortunately, it picks up the wrong anaconda environment and therefore the wrong python although building PyCall in verbose mode shows that the correct python and libpython is found.

julia> using Pkg

julia> ENV["PYTHON"] = "/home/spiess/anaconda3/envs/thesis/bin/python"
"/home/spiess/anaconda3/envs/thesis/bin/python"

julia> Pkg.build("PyCall", verbose=true)
   Building Conda ─→ `~/.julia/packages/Conda/3rPhK/deps/build.log`
   Building PyCall → `~/.julia/packages/PyCall/zqDXB/deps/build.log`
[ Info: PyCall is using /home/spiess/anaconda3/envs/thesis/bin/python (Python 3.7.7) at /home/spiess/anaconda3/envs/thesis/bin/python, libpython = /mnt/antares_raid/home/spiess/anaconda3/envs/thesis/lib/libpython3.7m.so.1.0
[ Info: /mnt/antares_raid/home/spiess/.julia/packages/PyCall/zqDXB/deps/deps.jl has not changed
[ Info: /home/spiess/.julia/prefs/PyCall has not changed

julia> using PyCall

julia> PyCall.libpython
"/mnt/antares_raid/home/spiess/anaconda3/envs/twoears_conda/lib/libpython3.6m.so.1.0"

I want it to use the environment "thesis" and not "twoears_conda".

I'm also wondering why

julia> PyCall.conda
false

as the python comes from an anaconda environment. Or does this property refer to the conda which is shipped with PyCall?

I'm using the newest version of julia (1.5.2) and PyCall (1.91.4).

I would really appreciate you help. Thanks in advance,
Heiner

[h-spiess]

I solved it right after. I ran the build of PyCall in VSCode and after restarting julia everything worked as expected.