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Fix operator overloading to allow use of built in operator in overload #178

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JulianKemmerer opened this issue Sep 17, 2023 · 0 comments
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@JulianKemmerer
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Operator overloading can't use built in version of operator in definition of overload. Fix this to separate user's version of built in vs built in...

Work around is to use the generated C code from the built in version as user code under different function name...

@JulianKemmerer JulianKemmerer added the bug Something isn't working label Sep 17, 2023
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