Q9 Palindrome Number - python & JavaScript

class Solution:
    def isPalindrome(self, x: int) -> bool:
        
        rev = 0
        temp = x
        
        while x>0:
            digit = x % 10
            rev = rev * 10 + digit
            x = int(x / 10)
        return 1 if temp == rev else 0

--------------JavaScript----------------

/**
 * @param {number} x
 * @return {boolean}
 */
var isPalindrome = function(x) {
    const temp = x;
    let res = 0;

    while (x > 0) {
        let rem = parseInt(x % 10);
        x = Math.trunc(x / 10);
        res = (res * 10) + rem
    }
    return temp == res
    
    
};