https://leetcode.com/problems/decode-ways/
A message containing letters from A-Z
is being encoded to numbers using the following mapping:
'A' -> 1
'B' -> 2
...
'Z' -> 26
Given a non-empty string containing only digits, determine the total number of ways to decode it.
The answer is guaranteed to fit in a 32-bit integer.
Example 1:
Input: s = "12"
Output: 2
Explanation: It could be decoded as "AB" (1 2) or "L" (12).
Example 2:
Input: s = "226"
Output: 3
Explanation: It could be decoded as "BZ" (2 26), "VF" (22 6), or "BBF" (2 2 6).
Example 3:
Input: s = "0"
Output: 0
Explanation: There is no character that is mapped to a number starting with '0'. We cannot ignore a zero when we face it while decoding. So, each '0' should be part of "10" --> 'J' or "20" --> 'T'.
Example 4:
Input: s = "1"
Output: 1
Constraints:
1 <= s.length <= 100
s
contains only digits and may contain leading zero(s).
- DP 思路
def solve(s):
if not s or len(s) == 0:
return 0
n = len(s)
dp = [0] * (1 + n)
dp[0] = 1
dp[1] = 1 if s[0] != '0' else 0
for i in range(2, n + 1):
if int(s[i-1]) != 0:
dp[i] += dp[i-1]
if 10 <= int(s[i-2:i]) <= 26:
dp[i] += dp[i-2]
return dp[n]