3sum [Medium]
Given an array S of n integers, are there elements a, b, c in S such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.
Note: The solution set must not contain duplicate triplets.
For example, given array S = [-1, 0, 1, 2, -1, -4],
A solution set is:
[
[-1, 0, 1],
[-1, -1, 2]
]
class Solution {
public List<List<Integer>> threeSum(int[] nums) {
Arrays.sort(nums);
Map<Integer, Integer> map = new HashMap<>(); //number, index
for (int i = 0; i < nums.length; i++) {
map.put(nums[i], i);
}
List<List<Integer>> results = new ArrayList<>();
for (int index1 = 0; index1 < nums.length; index1++) {
if (index1 != 0 && nums[index1] == nums[index1-1]) {
continue;
}
for (int index2 = index1+1; index2 < nums.length; index2++) {
if (index2 != index1+1 && nums[index2] == nums[index2-1]) {
continue;
}
int number1 = nums[index1];
int number2 = nums[index2];
int number3 = -(number1+number2);
Integer index3 = map.get(number3);
if (index3 != null && index3 > index2) {
results.add(Arrays.asList(number1, number2, number3));
}
}
}
return results;
}
}