# Brute Force
class Solution:
def rotateString(self, A: str, B: str) -> bool:
if not A and not B: # Corner Case
return True
for _ in range(len(A)): # 遍历去找
if A == B:
return True
A = self.shift(A) # 移一位
return False
def shift(self,str):
return str[1:] + str[0]
#时间复杂度O(N^2) 空间#时间复杂度O(N)