- 查找命中所需的时间与被查找的键的长度成正比；
- 查找未命中只需检查若干个字符。
单词查找树是由链接的结点所组成的数据结构，这些链接可能为空，也可能指向其他结点。每个结点都含有 R 条链接，其中 R 为字母表的大小（即字母表中字母的数量）。
值为空的结点在符号表中没有对应的键，它们的存在是为了简化单词查找树中的查找操作。
以被查找的字符为导向。单词查找树中每一个节点包含下一个可能出现的字符的链接，从根结点开始直至最后一个字母或者遇到空链接。
-
键的尾字符所对应的节点非空（一次命中）
-
键的尾字符所对应的节点为空（一次未命中）
-
查找结束于一条空链接（未命中）
与二叉查找树一样，插入前需要进行一次查找：
-
到达键的尾字符前遇到空链接。键不存在树中，需要为未被检查的每个字符创建节点
-
遇到空链接之前到达键的尾字符。将该节点的值设为键所对应的值（无论是否为空）。
字符串符号表： TrieST.java
内涵构造函数、size()、keys()、keysWithPrefix(String prefix)、keysThatMatch(String pattern)等
public class TrieST<Value> {
private static final int R = 256; // extended ASCII
private Node root; // root of trie
private int n; // number of keys in trie
// R-way trie node
private static class Node {
private Object val;
private Node[] next = new Node[R];
}
/**
* Initializes an empty string symbol table.
*/
public TrieST() {
}
public Value get(String key) {
if (key == null) throw new IllegalArgumentException("argument to get() is null");
Node x = get(root, key, 0);
if (x == null) return null;
return (Value) x.val;
}
public boolean contains(String key) {
if (key == null) throw new IllegalArgumentException("argument to contains() is null");
return get(key) != null;
}
private Node get(Node x, String key, int d) {
if (x == null) return null;
if (d == key.length()) return x;
char c = key.charAt(d);
return get(x.next[c], key, d+1);
}
public void put(String key, Value val) {
if (key == null) throw new IllegalArgumentException("first argument to put() is null");
if (val == null) delete(key);
else root = put(root, key, val, 0);
}
private Node put(Node x, String key, Value val, int d) {
if (x == null) x = new Node();
if (d == key.length()) {
if (x.val == null) n++;
x.val = val;
return x;
}
char c = key.charAt(d);
x.next[c] = put(x.next[c], key, val, d+1);
return x;
}
public int size() {
return n;
}
public boolean isEmpty() {
return size() == 0;
}
public Iterable<String> keys() {
return keysWithPrefix("");
}
public Iterable<String> keysWithPrefix(String prefix) {
Queue<String> results = new Queue<String>();
Node x = get(root, prefix, 0);
collect(x, new StringBuilder(prefix), results);
return results;
}
private void collect(Node x, StringBuilder prefix, Queue<String> results) {
if (x == null) return;
if (x.val != null) results.enqueue(prefix.toString());
for (char c = 0; c < R; c++) {
prefix.append(c);
collect(x.next[c], prefix, results);
prefix.deleteCharAt(prefix.length() - 1);
}
}
public Iterable<String> keysThatMatch(String pattern) {
Queue<String> results = new Queue<String>();
collect(root, new StringBuilder(), pattern, results);
return results;
}
private void collect(Node x, StringBuilder prefix, String pattern, Queue<String> results) {
if (x == null) return;
int d = prefix.length();
if (d == pattern.length() && x.val != null)
results.enqueue(prefix.toString());
if (d == pattern.length())
return;
char c = pattern.charAt(d);
if (c == '.') {
for (char ch = 0; ch < R; ch++) {
prefix.append(ch);
collect(x.next[ch], prefix, pattern, results);
prefix.deleteCharAt(prefix.length() - 1);
}
}
else {
prefix.append(c);
collect(x.next[c], prefix, pattern, results);
prefix.deleteCharAt(prefix.length() - 1);
}
}
public String longestPrefixOf(String query) {
if (query == null) throw new IllegalArgumentException("argument to longestPrefixOf() is null");
int length = longestPrefixOf(root, query, 0, -1);
if (length == -1) return null;
else return query.substring(0, length);
}
private int longestPrefixOf(Node x, String query, int d, int length) {
if (x == null) return length;
if (x.val != null) length = d;
if (d == query.length()) return length;
char c = query.charAt(d);
return longestPrefixOf(x.next[c], query, d+1, length);
}
public void delete(String key) {
if (key == null) throw new IllegalArgumentException("argument to delete() is null");
root = delete(root, key, 0);
}
private Node delete(Node x, String key, int d) {
if (x == null) return null;
if (d == key.length()) {
if (x.val != null) n--;
x.val = null;
}
else {
char c = key.charAt(d);
x.next[c] = delete(x.next[c], key, d+1);
}
// remove subtrie rooted at x if it is completely empty
if (x.val != null) return x;
for (int c = 0; c < R; c++)
if (x.next[c] != null)
return x;
return null;
}
public static void main(String[] args) {
// build symbol table from standard input
TrieST<Integer> st = new TrieST<Integer>();
for (int i = 0; !StdIn.isEmpty(); i++) {
String key = StdIn.readString();
st.put(key, i);
}
// print results
if (st.size() < 100) {
StdOut.println("keys(\"\"):");
for (String key : st.keys()) {
StdOut.println(key + " " + st.get(key));
}
StdOut.println();
}
StdOut.println("longestPrefixOf(\"shellsort\"):");
StdOut.println(st.longestPrefixOf("shellsort"));
StdOut.println();
StdOut.println("longestPrefixOf(\"quicksort\"):");
StdOut.println(st.longestPrefixOf("quicksort"));
StdOut.println();
StdOut.println("keysWithPrefix(\"shor\"):");
for (String s : st.keysWithPrefix("shor"))
StdOut.println(s);
StdOut.println();
StdOut.println("keysThatMatch(\".he.l.\"):");
for (String s : st.keysThatMatch(".he.l."))
StdOut.println(s);
}
}暂空