leaf_name携带 - 导致获取workerId报错

[wuweishuo]

Leaf/leaf-core/src/main/java/com/sankuai/inf/leaf/snowflake/SnowflakeZookeeperHolder.java

Lines 85 to 92 in 76301dc

	//表示新启动的节点,创建持久节点 ,不用check时间
	String newNode = createNode(curator);
	zk_AddressNode = newNode;
	String[] nodeKey = newNode.split("-");
	workerID = Integer.parseInt(nodeKey[1]);
	doService(curator);
	updateLocalWorkerID(workerID);
	LOGGER.info("[New NODE]can not find node on forever node that endpoint ip-{} port-{} workid-{},create own node on forever node and start SUCCESS ", ip, port, workerID);

workerID = Integer.parseInt(nodeKey[1]); 获取到的为leaf_name的值
改为workerID = Integer.parseInt(nodeKey[nodeKey.length - 1]);

[Issocala]

这里的nodeMap里面的数据格式类似于192.168.2.116:2184-0000000001，直接nodeKey[1]就已经获取到workerID了，leaf_name在snowflake节点下，所以并不会有问题。

[wuweishuo]

String newNode = createNode(curator); 返回的是全路径而不是节点名

[Issocala]

让我们将目光移至String[] nodeKey = newNode.split("-")这行，你会发现是的，workerID = Integer.parseInt(nodeKey[1]); 仍然在获取workerID。当然我们可以说改为nodeKey[nodeKey.length - 1]更为严谨。不过至少原来的设计并不会有什么问题。