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Using version 9.1.1, run new BigNumber(0).exponentiatedBy('-12345678901234567890123456789012345678901234567890').valueOf() Is return to infinity normal? #345

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Longqin88888 opened this issue Apr 26, 2023 · 1 comment

Longqin88888 commented Apr 26, 2023

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MikeMcl commented Apr 26, 2023

Yes, it is.

Math.pow(0, -123)    // Infinity

MikeMcl closed this as completed

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