Mistake in explanation of Ex.16.42 (c) #810
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Since the T is deduced to be plain T (i.e. plain, non-reference int), the val will be of type int&&. There's no int&& &&, since T is a plain type.
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Since the T is deduced to be plain T (i.e. plain, non-reference int), the val will be of type int&&. There's no int&& &&, since T is a plain type.