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The regression test 3D_Skew_Steady fails when np=2 as the Newton solver blows up. Possibly an error in marking boundaries or parent-child facets being unreliable in parallel? Output is below.
Solving
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Process 0: No Jacobian form specified for nonlinear variational problem.
Process 0: Differentiating residual form F to obtain Jacobian J = F'.Process 0: Solving nonlinear variational problem. Process 0: Newton iteration 0: r (abs) = 1.120e+06 (tol = 1.000e-06) r (rel) = 1.000e+00 (tol = 1.000e-05) Process 0: Newton iteration 1: r (abs) = 6.355e+05 (tol = 1.000e-06) r (rel) = 5.674e-01 (tol = 1.000e-05) Process 0: Newton iteration 2: r (abs) = 1.274e+06 (tol = 1.000e-06) r (rel) = 1.137e+00 (tol = 1.000e-05) Process 0: Newton iteration 3: r (abs) = 8.578e+05 (tol = 1.000e-06) r (rel) = 7.658e-01 (tol = 1.000e-05) Process 0: Newton iteration 4: r (abs) = 1.393e+07 (tol = 1.000e-06) r (rel) = 1.244e+01 (tol = 1.000e-05) Process 0: Newton iteration 5: r (abs) = 2.407e+08 (tol = 1.000e-06) r (rel) = 2.149e+02 (tol = 1.000e-05) Process 0: Newton iteration 6: r (abs) = 8.855e+07 (tol = 1.000e-06) r (rel) = 7.906e+01 (tol = 1.000e-05) Process 0: Newton iteration 7: r (abs) = 4.285e+07 (tol = 1.000e-06) r (rel) = 3.825e+01 (tol = 1.000e-05) Process 0: Newton iteration 8: r (abs) = 9.166e+07 (tol = 1.000e-06) r (rel) = 8.183e+01 (tol = 1.000e-05) Process 0: Newton iteration 9: r (abs) = 2.379e+13 (tol = 1.000e-06) r (rel) = 2.124e+07 (tol = 1.000e-05) Process 0: Newton iteration 10: r (abs) = 6.146e+12 (tol = 1.000e-06) r (rel) = 5.487e+06 (tol = 1.000e-05) Process 0: Newton iteration 11: r (abs) = 1.653e+12 (tol = 1.000e-06) r (rel) = 1.476e+06 (tol = 1.000e-05) Process 0: Newton iteration 12: r (abs) = 2.040e+12 (tol = 1.000e-06) r (rel) = 1.821e+06 (tol = 1.000e-05) Process 0: Newton iteration 13: r (abs) = 1.371e+14 (tol = 1.000e-06) r (rel) = 1.224e+08 (tol = 1.000e-05) Process 0: Newton iteration 14: r (abs) = 3.583e+13 (tol = 1.000e-06) r (rel) = 3.198e+07 (tol = 1.000e-05) Process 0: Newton iteration 15: r (abs) = 1.344e+15 (tol = 1.000e-06) r (rel) = 1.200e+09 (tol = 1.000e-05) Process 0: Newton iteration 16: r (abs) = 3.470e+14 (tol = 1.000e-06) r (rel) = 3.098e+08 (tol = 1.000e-05) Process 0: Newton iteration 17: r (abs) = 1.248e+14 (tol = 1.000e-06) r (rel) = 1.114e+08 (tol = 1.000e-05) Process 0: Newton iteration 18: r (abs) = 8.591e+14 (tol = 1.000e-06) r (rel) = 7.670e+08 (tol = 1.000e-05) Process 0: Newton iteration 19: r (abs) = 2.622e+15 (tol = 1.000e-06) r (rel) = 2.341e+09 (tol = 1.000e-05) Process 0: Newton iteration 20: r (abs) = 7.180e+14 (tol = 1.000e-06) r (rel) = 6.410e+08 (tol = 1.000e-05) Process 0: Newton iteration 21: r (abs) = 7.329e+14 (tol = 1.000e-06) r (rel) = 6.543e+08 (tol = 1.000e-05) Process 0: Newton iteration 22: r (abs) = 2.961e+14 (tol = 1.000e-06) r (rel) = 2.643e+08 (tol = 1.000e-05) Process 0: Newton iteration 23: r (abs) = 7.600e+13 (tol = 1.000e-06) r (rel) = 6.785e+07 (tol = 1.000e-05) Process 0: Newton iteration 24: r (abs) = 2.846e+14 (tol = 1.000e-06) r (rel) = 2.541e+08 (tol = 1.000e-05) Process 0: Newton iteration 25: r (abs) = 3.824e+14 (tol = 1.000e-06) r (rel) = 3.414e+08 (tol = 1.000e-05) Process 0: Newton iteration 26: r (abs) = 1.306e+14 (tol = 1.000e-06) r (rel) = 1.166e+08 (tol = 1.000e-05) Process 0: Newton iteration 27: r (abs) = 4.862e+13 (tol = 1.000e-06) r (rel) = 4.340e+07 (tol = 1.000e-05) Process 0: Newton iteration 28: r (abs) = 2.073e+13 (tol = 1.000e-06) r (rel) = 1.851e+07 (tol = 1.000e-05) Process 0: Newton iteration 29: r (abs) = 3.471e+14 (tol = 1.000e-06) r (rel) = 3.099e+08 (tol = 1.000e-05) Process 0: Newton iteration 30: r (abs) = 1.154e+14 (tol = 1.000e-06) r (rel) = 1.030e+08 (tol = 1.000e-05) Process 0: Newton iteration 31: r (abs) = 3.055e+13 (tol = 1.000e-06) r (rel) = 2.728e+07 (tol = 1.000e-05) Process 0: Newton iteration 32: r (abs) = 3.287e+13 (tol = 1.000e-06) r (rel) = 2.934e+07 (tol = 1.000e-05) Process 0: Newton iteration 33: r (abs) = 1.092e+13 (tol = 1.000e-06) r (rel) = 9.745e+06 (tol = 1.000e-05) Process 0: Newton iteration 34: r (abs) = 5.564e+12 (tol = 1.000e-06) r (rel) = 4.967e+06 (tol = 1.000e-05) Process 0: Newton iteration 35: r (abs) = 9.925e+12 (tol = 1.000e-06) r (rel) = 8.861e+06 (tol = 1.000e-05) Process 0: Newton iteration 36: r (abs) = 1.294e+13 (tol = 1.000e-06) r (rel) = 1.155e+07 (tol = 1.000e-05) Process 0: Newton iteration 37: r (abs) = 9.416e+13 (tol = 1.000e-06) r (rel) = 8.407e+07 (tol = 1.000e-05) Process 0: Newton iteration 38: r (abs) = 2.460e+13 (tol = 1.000e-06) r (rel) = 2.196e+07 (tol = 1.000e-05) Process 0: Newton iteration 39: r (abs) = 6.238e+14 (tol = 1.000e-06) r (rel) = 5.569e+08 (tol = 1.000e-05) Process 0: Newton iteration 40: r (abs) = 1.583e+14 (tol = 1.000e-06) r (rel) = 1.414e+08 (tol = 1.000e-05)
The text was updated successfully, but these errors were encountered:
The regression test 3D_Skew_Steady fails when np=2 as the Newton solver blows up. Possibly an error in marking boundaries or parent-child facets being unreliable in parallel? Output is below.
The text was updated successfully, but these errors were encountered: