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Define decomposition for qml.ControlledQubitUnitary
#2322
Comments
Hey @antalszava, I just started looking into this and would like to work on this, if that's okay. I quite like the Idea of using |
Hi @MoritzWillmann, apologies for the delayed response here! For sure, feel free to go for it. 🙂 Using |
Hi @antalszava, sorry for the super delayed response 😞 |
Hi @MoritzWillmann, a bit of both 🙂 Specifically here, extending |
Feature details
Logic to decompose
qml.ControlledQubitUnitary
would be great to have. One potential solution could be to regardqml.ControlledQubitUnitary
as aqml.QubitUnitary
and use the decomposition of QubitUnitary (note: that this is only defined for the two-qubit case).Also see #2320.
Implementation
No response
How important would you say this feature is?
1: Not important. Would be nice to have.
Additional information
No response
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