Misleading AST for modulo operator combined with multiplication

[EmilyBourne]

When a modulo operator is combined with a multiplication redbaron does not interpret the code in the same way as python.

E.g:

a % 2 * 4

In python this is equivalent to:

(a % 2) * 4

however redbaron reads it as:

a % (2 * 4)

as shown here:

> red = RedBaron("a % 2 * 4")

> red.help(deep=True)
0 -----------------------------------------------------
BinaryOperatorNode()
  # identifiers: binary_operator, binary_operator_, binaryoperator, binaryoperatornode
  value='%'
  first ->
    NameNode()
      # identifiers: name, name_, namenode
      value='a'
  second ->
    BinaryOperatorNode()
      # identifiers: binary_operator, binary_operator_, binaryoperator, binaryoperatornode
      value='*'
      first ->
        IntNode()
          # identifiers: int, int_, intnode
          value='2'
      second ->
        IntNode()
          # identifiers: int, int_, intnode
          value='4'

[EmilyBourne]

This is due to an error in baron: PyCQA/baron#162