[Feature] : Capacitance in a parallel plate capacitor

[GAVINESHWAR]

Description

The capacitance of a parallel plate capacitor with a dielectric is given by 𝐶=𝜅𝜖0𝐴/𝑑 where 𝜅 is the dielectric constant, 𝜖0 is the permittivity of free space, 𝐴 is the area of the plates, and d is the distance between the plates. This formula accounts for the increased capacitance due to the dielectric material, which enhances the capacitor's ability to store charge.

Formula:
𝐶=𝜅𝜖0𝐴/𝑑

Inputs: Dielectric constant (κ),
Permittivity of free space (𝜖0),
Area of the plates (A),
Distance between the plates (d)
Output: Capacitance (C)

@Rakesh9100, please assign me this issue to make contribution to the project sir.

Thank you

Screenshots

Checklist

• I have checked the existing issues.
• I follow Contributing Guidelines of this project.
• I am a GSSOC'24 contributor.
• I am a IWOC'24 contributor.
• I am a JWOC'24 contributor.
• I am a SWOC'24 contributor.

Code of Conduct

• I agree to follow this project's "Code of Conduct".

[github-actions]

Hey @GAVINESHWAR, Welcome to the project CalcDiverse! 🎊
Thanks for opening an issue! 🙌 Please wait for the issue to be assigned. Happy Coding!! ✨

[jessicachawla]

@GAVINESHWAR consider giving output for both series and parallel. You can ask in input if it's parallel or series connection

[GAVINESHWAR]

@jessicachawla mam, parallel plate capacitors are a type of capacitor that have an arrangement of electrodes and insulating material (dielectric). This calculator determines the capacitance of a single capacitor.

If required, I can add another calculator for finding the equivalent capacitance of capacitors connected in parallel and series combinations.

This will look like this mam

Thank you mam

[jessicachawla]

Looks good
@Rakesh9100 this issue can be assigned

[GAVINESHWAR]

@Rakesh9100 assign me this issue to make contribution to the project sir.

Thank you

[GAVINESHWAR]

@Rakesh9100 assign me this issue to make contribution to the project sir, It was checked the jessicachawla .

Thank you

[Rakesh9100]

Go ahead @GAVINESHWAR