A binary tree is univalued if every node in the tree has the same value.
Return true if and only if the given tree is univalued.
Example 1:
Input: [1,1,1,1,1,null,1]
Output: true
Example 2:
Input: [2,2,2,5,2]
Output: false
Note:
- The number of nodes in the given tree will be in the range [1, 100].
- Each node's value will be an integer in the range [0, 99].
- Method 1: dfs
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ class Solution { private int pre; public boolean isUnivalTree(TreeNode root) { pre = root.val; return check(root.left) && check(root.right); } private boolean check(TreeNode node){ if(node == null) return true; else if(pre != node.val) return false; else{ return check(node.left) && check(node.right); } } }