output problem

[Phoenix1112]

I save the results of the program as -o results.txt. but if there is no parameter in a url address, it writes the same url address without parameters to the output file. I don't understand why you set it this way. If no parameter is found, it doesn't make much sense to add it to the output file. If you examine both this problem and the other issue(https://github.com/Sh1Yo/x8/issues/24) I created and update the program, the program will be much better.

[Sh1Yo]

I made it this way to clarify whether the specific url was checked. You can easily remove it from the list later by using a bit of coding or grep. Feel free to reopen issue, if you think that there's really a problem in printing output without found parameters.

[Phoenix1112]

@Sh1Yo I get all the url addresses from the url list and there are also url addresses with parameters in these url addresses. In such a scenario, if she writes a url address with a parameter to the output, I cannot understand which is the new url and which is the old url. because your program will write the parameterized url address to the output with parameters even if it does not find a result.
Therefore, it is useful for your program to print it out only when it finds a new parameter.

[Phoenix1112]

@Sh1Yo ??

[Sh1Yo]

There's a possibility that this thing will get implemented in the next version, but probably it's easier for you to just change your program's logic. I can't customize my tool to suit everyone's needs.