Given a binary tree, return the postorder traversal of its nodes' values.
For example: Given binary tree {1,#,2,3},
1
\
2
/
3
return [3,2,1].
Note: Recursive solution is trivial, could you do it iteratively?
见程序注释
0145.binary-tree-postorder-traversal
Folders and files
| Name | Name | Last commit message | Last commit date | |
|---|---|---|---|---|
parent directory.. | ||||