Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
#解析 新建一个指针指向要返回的头节点之前的那个节点。之后不断插入l1 和 l2 中最小值的那个节点即可。
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) {
ListNode head(INT_MIN);
ListNode* tail = &head;
while(l1 && l2){
if(l1->val < l2->val){
tail->next = l1;
l1 = l1 -> next;
}
else{
tail -> next = l2;
l2 = l2 -> next;
}
tail = tail -> next;
}
tail -> next = l1 ? l1 : l2;
return head.next;
}
};