字符串中字母的出现次数

[Sunny-117]

No description provided.

[GlintonLiao]

const str = "ABCabc123"
let res = 0
for (const c of str)
    if ((c >= 'a' && c <= 'z') || (c >= 'A' && c <= 'Z'))
        res++
console.log(res)  // 6

[bearki99]

function count(str){
    let res = 0;
    for(let i = 0; i < str.length; i++){
        if(str[i] >= 'a' && str[i] <= 'z' || (str[i] >= 'A' && str[i] <= 'Z')) res++;
    }
    return res;
}
console.log(count("ABCabc123"));

如果是要统计每个字母的次数，可以用map

[fencer-yd]

const reg = /[^a-zA-Z]/g;
const str = "ABCabc123";
console.log(str.replaceAll(reg, '').length)

[Banks1y]

const str = "ABCabc123";
let res = str.split("").reduce((pre, cur) => {
  if (!pre[cur]) pre[cur] = 1;
  else pre[cur]++;
  return pre;
}, {});
console.log(res);

[kangkang123269]

function countCharacters(str) {
    let charCount = {};
    for(let i = 0; i < str.length; i++) {
        let char = str[i];
        if(char.match(/[a-zA-Z]/i)) { // 只考虑字母
            if(charCount[char]) {
                charCount[char]++;
            } else {
                charCount[char] = 1;
            }
        }
    }
    return charCount;
}