打印出 1~10000 以内的对称数

[Sunny-117]

No description provided.

[lxy-Jason]

function isSymmetryNum(start,end){
    for(let i = start; i < end + 1; i++){
        let str = String(i);
        if(str.length <= 1) continue;
        if(str.split("").reverse().join("") === str){
            console.log(i);
        }
    }
}
isSymmetryNum(1,10000)

[weirong111]

function getDuicheng() {
  const res = [];
  for (let i = 1; i < 10; i++) {
    res.push(i);
    res.push(i * 11);
    for (let j = 0; j < 10; j++) {
      res.push(i * 101 + j * 10); //101-999
      res.push(i * 1001 + j * 110); //1001-9999
    }
  }
  return res;
}

[bearki99]

const res = [];
function getSymNum() {
  for (let i = 1; i <= 10000; i++) {
    let str1 = i + "";
    if (judgeSym(str1)) res.push(i);
  }
}
function judgeSym(str) {
  let l = 0,
    r = str.length - 1;
  while (l < r) {
    if (str[l] !== str[r]) return false;
    r--;
    l++;
  }
  return true;
}
getSymNum();
console.log(res);

简单的双指针

[MoYuanJun]

const isSymmetryNum = (start, end) => {
const res = []

for (let i = start; i < end; i++) {
const toStr = String(i)
const reverse = [...toStr].reverse().join('')
if (toStr === reverse) {
res.push(i)
}
}

return res
}

[fangbw17]

function symmetric(num) {
    const result = [];

    const nums = Array.from({ length: num }, (_, i) => 1 + i);
    while (nums.length > 0) {
        const lastNum = nums.pop();
        if (String(lastNum).split("").reverse().join("") === String(lastNum)) {
            result.push(lastNum);
        }
    }
    return result;
}